19. Proof of Theorem 18.1

Back

Consider iterations (18.11). Since Φ0 0 satisfies all conditions of Lemmas

18.1–18.3, it follows from (18.11) for j = 0 that

_Φ1(y, ψ, τ, ε)_ sup

G

___

b

x

___

_

τ

_yξ,0

τ

_dξ n

γ1

c1K_y_ d1_y_,

___

y

Φ1(y, ψ, τ, ε)

___

sup

G

___

b

x

___

_

τ

___

y

yξ,0

τ

__ _

dξ

n

γ1

c1K d2.

To estimate

___

∂ψ

Φ1(y, ψ, τ, ε)

__ _

, we use inequalities (

18.22), the first of which

yields

___

∂ψ

ψξ

τ (ψ, ε)

___

m +

___

∂ψ

(ψξ

τ (ψ, ε) ψ)

___

m + c4εα(1 + ξ τ )ec4εα(ξτ)

m + e2c4εα(ξτ) (m + 1)e

1

4 γ(ξτ)

Section 19 Proof of Theorem 18.1 219

for ξ τ and 2c4εα0

1

4γ1. Then

___

∂ψ

Φ1(y, ψ, τ, ε)

___

_

2nc1c5

1

γ2

+ n2c1c1K

1

γ1

+ mnc1(m + 1)K

4

3γ1

_

_y_

d3_y_,

provided that hd3 1. The constants d1, d2, and d3 in the inequalities presented

above will be fixed in what follows. Consider the integral obtained from

(18.11) for j = 0 by differentiation with respect to τ under the integral sign.

Estimates (18.22) and (18.24) yield

_

τ

___

∂τ

(b0 _b)

__ _

dξ

c5_y_

__ω(τ )_

ε

+ 1

_

nc1

_

τ

e

γ2(ξτ)dξ

+ (nc1εα0

+ m)nc1c4K_y_

__ω(τ )_

ε

+ 1

_ _

τ

e

3

4 γ1(ξτ)dξ.

The estimates presented above guarantee the uniform convergence of the improper

integrals

_

τ

(b0 _b)dξ,

_

τ

y

(b0 _b)dξ,

_

τ

∂ψ

(b0 _b)dξ,

_

τ

∂τ

(b0 _b)dξ

on the set

y Ph, ψ Rm, τ [T,T], ε [Δ, ε0], (19.1)

where T > 0 and Δ > 0 (Δ< ε0) are arbitrary. Then, for every ε [Δ, ε0],

the function Φ1(y, ψ, τ, ε) is continuously differentiable with respect to y, ψ,

and τ from set (19.1) and satisfies Eq. (18.14) with j = 0 for these values of

y, ψ, τ, and ε. Since Δ and T are arbitrary, we obtain relation (18.14) for all

(y, ψ, τ, ε) G.

Now assume that, for all j = 1, s, s > 1, the functions Φj(y, ψ, τ, ε) are

continuously differentiable with respect to (y, ψ, τ) Ph × Rm × R for every

value of the parameter ε and satisfy the inequalities

220 Integral Manifolds Chapter 3

_Φj_ d1_y_,

___

y

Φj

___

d2,

___

∂ψ

Φj

___

d3_y_ (19.2)

and Eq. (18.14) (y, ψ, τ, ε) G. Using Lemmas 18.1–18.3 for j = s and

estimates (18.15) and (18.22), we deduce from (18.11) that

_Φs+1(y, ψ, τ, ε)_

_

nc1

1

γ1

K(1 + c1εα0

d1) +

1

γ1

K sup

G

___

b

ϕ

__ _

d1

_

_y_.

Since γ1 >

γ

2

and

K

γ1

sup

G

___

b

ϕ

___

2

γ

K sup

G

___

b

ϕ

___

= σ0 < 1,

for d1εα0

1 we get

_Φs+1(y, ψ, τ, ε)_

_

nc1

1

γ1

K(1 + c1) + σ0d1

_

_y_ d1_y_,

where

d1 = nc1(1 + c1)K

γ1(1 σ0) .

By analogy, for d2εα0

1 we obtain

___

y

Φs+1(y, ψ, τ, ε)

___

2nc1(1 + c1)

γ1(1 σ0) K d2.

We now represent

∂ψ

Φs+1(y, ψ, τ, ε) in the form

∂ψ

Φs+1(y, ψ, τ, ε)

=

_

τ

_bs

y

+

_bs

y

Xs

ϕ

+ bs

ϕ

_Φs

y

_yξ,s

τ

∂ψ

dξ

_

τ

_(bs _b)

y

Xs

ϕ

+ _b

y

_Xs

ϕ

X

ϕ

_

+ (bs _b)

ϕ

_∂ψξ

τ

∂ψ

dξ

_

τ

_bs

y

Xs

ϕ

Φs

ϕ

∂ψξ

τ

∂ψ

+ bs

ϕ

Φs

ϕ

(ψξ

τ ψ)

∂ψ

+ bs

ϕ

Φs

ϕ

_

dξ

Section 19 Proof of Theorem 18.1 221

and use the inequalities

_Φs(yξ,s

τ , ψξ

τ, ξ, ε)_ d1K_y_e

γ1(ξτ),

___

ϕ

Φs(yξ,s

τ , ψξ

τ, ξ, ε)

___

d3K_y_e

γ1(ξτ), ξ τ.

Then, for c1εα0

1, d3εα0

1, and hd3 1, we get

___

∂ψ

Φs+1(y, ψ, τ, ε)

___

(c10 + σ0d3)_y_ c10

1 σ0

_y_ d3_y_,

where

c10 =

2

γ2

(n + (n + m)d2)c1c5 +

4

3γ1

c1K(m + 1)[(n + m)2(1 + 2d1) + nd1]

+

4

3γ1

n(m + 1)c1c1K +

4

9γ2

1

(4 + 3γ1)mc1c4K.

Thus, by the method of mathematical induction, we establish that, for sufficiently

small h > 0 and ε0 > 0, inequalities (19.2) with the constants d1, d2,

and d3 defined above hold for all j 0 and (y, ψ, τ, ε) G. Moreover, the

fact that the norms of the matrices

yξ,j

τ ,

y

yξ,j

τ ,

∂ψ

yξ,j

τ ,

∂τ

yξ,j

τ

tend exponentially to zero as ξ guarantees the uniform convergence [on

set (19.1)] of the improper integral (18.11) and the integrals obtained from it by

differentiation with respect to y, ψ, and τ under the integral sign. Therefore,

the functions Φj(y, ψ, τ, ε), j 0, are continuously differentiable with respect

to y, ψ, and τ for every fixed ε from set (19.1) and satisfy Eq. (18.14). Since

Δ and T are arbitrary, equality (18.14) holds for all (y, ψ, τ, ε) G, and the

functions Φj(y, ψ, τ, ε) have continuous partial derivatives of the first order with

respect to (y, ψ, τ) Ph × Rm × R for every ε (0, ε0].

We now prove that the matrices

y

Φj(y, ψ, τ, ε) and

∂ψ

Φj(y, ψ, τ, ε) satisfy

the Lipschitz condition with respect to the variables y and ψ. Using Lemma

18.4 for j = 0 and the inequalities

_ψξ

τ (ψ, ε) ψξ

τ (ψ, ε)_ [1 + c4εα(1 + ξ τ )ec4εα(ξτ)]_ψ ψ_,

_yξ,j

τ (y, ψ, ε) yξ,j

τ (y, ψ, ε)_

Ke

γ1(ξτ)]_y y_ + c5h(1 + hd3)e

γ2(ξτ)_ψ ψ_, ξ τ, (19.3)

222 Integral Manifolds Chapter 3

which follow from relations (18.22) and (18.23) and Lemma 18.2, we deduce the

following estimate from (18.11):

___

y

Φ1(y, ψ, τ, ε)

y

Φ1(y, ψ, τ, ε)

___

Knc1

_ c6

γ3

+ n

2γ1

K + nc5h

1

γ1 + γ2

(1 + hd3)

+ (m + nc1εα0

)

_ 1

γ2

+

4

4γ2 γ1

__

(_y y_ + _ψ ψ_)

μ(_y y_ + _ψ ψ_).

Here, μ > 0 is a constant, which will be fixed in what follows. Assume that

inequalities (18.25) are satisfied for all j = 1, s, s > 1. Then

___

y

Φs+1(y, ψ, τ, ε)

y

Φs+1(y, ψ, τ, ε)

___

c1(n + d2(n + m))

_

τ

___

y

yξ,s

τ (y, ψ, ε)

y

yξ,s

τ (y, ψ, ε)

__ _

dξ

+

_

c1(1 + d2 + d3h)K[(1 + d2)(n + m)2 + nd2]

+

_

nc1c1εα0

+ sup

G

___

b

ϕ

___

_

Kμ

_ _

τ

(_yξ,s

τ (y, ψ, ε) yξ,s

τ (y, ψ, ε)_

+ _ψξ

τ (ψ, ε) ψξ

τ (ψ, ε)_)e

γ1(ξτ)dξ.

Choosing h > 0 and ε0 > 0 so small that hμ 1 and εα0

μ 1 and using

Lemma 18.4 and estimates (19.3), we get

___

y

Φs+1(y, ψ, τ, ε)

y

Φs+1(y, ψ, τ, ε)

___

c11(_y y_ + _ψ ψ_) + sup

G

___

b

ϕ

___

1

2γ1

K2μ_y y_

+ sup

G

___

b

ϕ

___

1

γ1

Kμ_ψ ψ_, (19.4)

Section 19 Proof of Theorem 18.1 223

where

c11 = c1[n + d2(n + m)]

2

γ3

c6

+ c1K[(2 + d2)(nd2 + (1 + d2)(n + m)2 + nc1)]

_ 2c5

(γ1 + γ2)d3

+ K

2γ1

_

+ mc1K

_ 2c5

γ1 + γ2

+

4

9γ2

1

c4(4 + 3γ1)

_

.

Since γ1 >

1

2γ and, according to condition (18.15), the constant

σ0 = K

γ

sup

G

___

b

ϕ

___

max{2;K}

is less than 1, it follows from inequality (19.4) that

___

y

Φs+1(y, ψ, τ, ε)

y

Φs+1(y, ψ, τ, ε)

___

(c11 + μσ0)(_y y_ + _ψ ψ_) μ(_y y_ + _ψ ψ_),

μ = c11

1 σ0

.

Thus, we have established inequalities (18.25) for all j 0.

By analogy, using Lemma 18.5, for sufficiently small h > 0 and ε0 > 0 one

can prove inequalities (18.26) for all j 0 with the constant ν independent of

ε and h.

Consider the problem of the convergence of the sequence {Φj(y, ψ, τ, ε)} on

the set G. In view of inequalities (18.27) and (18.31), relation (18.11) yields

_Φj+1(y, ψ, τ, ε) Φj(y, ψ, τ, ε)_

_

(n + (m + nc1εα0

)d2) c1

γ5

_y_2 + sup

G

___

b

ϕ

___

1

γ1

K_y_

_

sup

G

vj1

or

sup

G

vj

_

σ0 + c1(n + m)d2

1

γ5

h

_

sup

G

vj1. (19.5)

For small h > 0, the expression in the square brackets on the right-hand side of

inequality (19.5) can be estimated by a constant c12 less than 1. Consequently,

the inequalities

224 Integral Manifolds Chapter 3

sup

G

vj c12 sup

G

vj1, c12 < 1, sup

G

v0 d1

imply that the numerical series

,

j=0

sup

G

vj is convergent, and, hence, the functional

sequence {Φj(y, ψ, τ, ε)} converges uniformly on the set G to the limit

function

Φ(y, ψ, τ, ε) = lim

j→∞

Φj(y, ψ, τ, ε)

continuous in y, ψ, and τ.

By analogy, using estimates (18.28) and (18.29) we prove the uniform convergence

of the sequences

_

∂ψ

Φj(y, ψ, τ, ε)

_

and

_

y

Φj(y, ψ, τ, ε)

_

on the

set G.

Consider the sequence

_

∂τ

Φj(y, ψ, τ, ε)

_

each element of which is determined

by equality (18.14). The smoothness conditions for the right-hand side of

system (18.1) and the uniform convergence of the sequences {Φj},

_

∂ψ

Φj

_

,

and

_

y

Φj

_

on the set G yield the uniform convergence of the sequence

_

∂τ

Φj

_

on set (19.1). Therefore, the limit function Φ(y, ψ, τ, ε) is continuous

in y, ψ, and τ for every fixed ε from set (19.1). Passing to the limit as

j in Eq. (18.4), we obtain Eq. (18.10) for all y, ψ, τ, and ε from set

(19.1). Since T and Δ are arbitrary, we get Eq. (18.10) for any (y, ψ, τ, ε) G.

The Lipschitz conditions (18.17) follow from inequalities (18.25) and (18.26).

Theorem 18.1 is proved.