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Авторы: 111 А Б В Г Д Е Ж З И Й К Л М Н О П Р С Т У Ф Х Ц Ч Ш Щ Э Ю Я
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19. Proof of Theorem 18.1
Consider iterations (18.11). Since Φ0 ≡ 0 satisfies all conditions of Lemmas
18.1–18.3, it follows from (18.11) for j = 0 that
_Φ1(y, ψ, τ, ε)_ ≤ sup
G
___
∂b
∂x
___
∞ _
τ
_yξ,0
τ
_dξ ≤ n
γ1
c1K_y_ ≤ d1_y_,
___
∂
∂y
Φ1(y, ψ, τ, ε)
___
≤ sup
G
___
∂b
∂x
___
∞ _
τ
___∂
∂y
yξ,0
τ
__ _
dξ ≤
n
γ1
c1K ≤ d2.
To estimate
___
∂
∂ψ
Φ1(y, ψ, τ, ε)
__ _
, we use inequalities (
18.22), the first of which
yields
___
∂
∂ψ
ψξ
τ (ψ, ε)
___
≤ m +
___
∂
∂ψ
(ψξ
τ (ψ, ε) − ψ)
___
≤ m + c4εα(1 + ξ − τ )ec4εα(ξ−τ)
≤ m + e2c4εα(ξ−τ) ≤ (m + 1)e
1
4 γ(ξ−τ)
Section 19 Proof of Theorem 18.1 219
for ξ ≥ τ and 2c4εα0
≤ 1
4γ1. Then
___
∂
∂ψ
Φ1(y, ψ, τ, ε)
___
≤
_
2nc1c5
1
γ2
+ n2c1c1K
1
γ1
+ mnc1(m + 1)K
4
3γ1
_
_y_
≤ d3_y_,
provided that hd3 ≤ 1. The constants d1, d2, and d3 in the inequalities presented
above will be fixed in what follows. Consider the integral obtained from
(18.11) for j = 0 by differentiation with respect to τ under the integral sign.
Estimates (18.22) and (18.24) yield
∞ _
τ
___
∂
∂τ
(b0 −_b)
__ _
dξ
≤ c5_y_
__ω(τ )_
ε
+ 1
_
nc1
∞ _
τ
e
−γ2(ξ−τ)dξ
+ (nc1εα0
+ m)nc1c4K_y_
__ω(τ )_
ε
+ 1
_ ∞ _
τ
e
−3
4 γ1(ξ−τ)dξ.
The estimates presented above guarantee the uniform convergence of the improper
integrals
∞ _
τ
(b0 −_b)dξ,
∞ _
τ
∂
∂y
(b0 −_b)dξ,
∞ _
τ
∂
∂ψ
(b0 −_b)dξ,
∞ _
τ
∂
∂τ
(b0 −_b)dξ
on the set
y ∈ Ph, ψ∈ Rm, τ ∈ [−T,T], ε∈ [Δ, ε0], (19.1)
where T > 0 and Δ > 0 (Δ< ε0) are arbitrary. Then, for every ε ∈ [Δ, ε0],
the function Φ1(y, ψ, τ, ε) is continuously differentiable with respect to y, ψ,
and τ from set (19.1) and satisfies Eq. (18.14) with j = 0 for these values of
y, ψ, τ, and ε. Since Δ and T are arbitrary, we obtain relation (18.14) for all
(y, ψ, τ, ε) ∈ G.
Now assume that, for all j = 1, s, s > 1, the functions Φj(y, ψ, τ, ε) are
continuously differentiable with respect to (y, ψ, τ) ∈ Ph × Rm × R for every
value of the parameter ε and satisfy the inequalities
220 Integral Manifolds Chapter 3
_Φj_ ≤ d1_y_,
___
∂
∂y
Φj
___
≤ d2,
___
∂
∂ψ
Φj
___
≤ d3_y_ (19.2)
and Eq. (18.14) ∀(y, ψ, τ, ε) ∈ G. Using Lemmas 18.1–18.3 for j = s and
estimates (18.15) and (18.22), we deduce from (18.11) that
_Φs+1(y, ψ, τ, ε)_ ≤
_
nc1
1
γ1
K(1 + c1εα0
d1) +
1
γ1
K sup
G
___
∂b
∂ϕ
__ _
d1
_
_y_.
Since γ1 >
γ
2
and
K
γ1
sup
G
___
∂b
∂ϕ
___
<
2
γ
K sup
G
___
∂b
∂ϕ
___
= σ0 < 1,
for d1εα0
≤ 1 we get
_Φs+1(y, ψ, τ, ε)_ ≤
_
nc1
1
γ1
K(1 + c1) + σ0d1
_
_y_ ≤ d1_y_,
where
d1 = nc1(1 + c1)K
γ1(1 − σ0) .
By analogy, for d2εα0
≤ 1 we obtain
___
∂
∂y
Φs+1(y, ψ, τ, ε)
___
≤ 2nc1(1 + c1)
γ1(1 − σ0) K ≡ d2.
We now represent
∂
∂ψ
Φs+1(y, ψ, τ, ε) in the form
∂
∂ψ
Φs+1(y, ψ, τ, ε)
= −
∞ _
τ
_∂bs
∂y
+
_∂bs
∂y
∂Xs
∂ϕ
+ ∂bs
∂ϕ
_∂Φs
∂y
_∂yξ,s
τ
∂ψ
dξ
−
∞ _
τ
_∂(bs −_b)
∂y
∂Xs
∂ϕ
+ ∂_b
∂y
_∂Xs
∂ϕ
− ∂X
∂ϕ
_
+ ∂(bs −_b)
∂ϕ
_∂ψξ
τ
∂ψ
dξ
−
∞ _
τ
_∂bs
∂y
∂Xs
∂ϕ
∂Φs
∂ϕ
∂ψξ
τ
∂ψ
+ ∂bs
∂ϕ
∂Φs
∂ϕ
∂(ψξ
τ − ψ)
∂ψ
+ ∂bs
∂ϕ
∂Φs
∂ϕ
_
dξ
Section 19 Proof of Theorem 18.1 221
and use the inequalities
_Φs(yξ,s
τ , ψξ
τ, ξ, ε)_ ≤ d1K_y_e
−γ1(ξ−τ),
___
∂
∂ϕ
Φs(yξ,s
τ , ψξ
τ, ξ, ε)
___
≤ d3K_y_e
−γ1(ξ−τ), ξ≥ τ.
Then, for c1εα0
≤ 1, d3εα0
≤ 1, and hd3 ≤ 1, we get
___
∂
∂ψ
Φs+1(y, ψ, τ, ε)
___
≤ (c10 + σ0d3)_y_ ≤ c10
1 − σ0
_y_ ≡ d3_y_,
where
c10 =
2
γ2
(n + (n + m)d2)c1c5 +
4
3γ1
c1K(m + 1)[(n + m)2(1 + 2d1) + nd1]
+
4
3γ1
n(m + 1)c1c1K +
4
9γ2
1
(4 + 3γ1)mc1c4K.
Thus, by the method of mathematical induction, we establish that, for sufficiently
small h > 0 and ε0 > 0, inequalities (19.2) with the constants d1, d2,
and d3 defined above hold for all j ≥ 0 and (y, ψ, τ, ε) ∈ G. Moreover, the
fact that the norms of the matrices
yξ,j
τ ,
∂
∂y
yξ,j
τ ,
∂
∂ψ
yξ,j
τ ,
∂
∂τ
yξ,j
τ
tend exponentially to zero as ξ → ∞ guarantees the uniform convergence [on
set (19.1)] of the improper integral (18.11) and the integrals obtained from it by
differentiation with respect to y, ψ, and τ under the integral sign. Therefore,
the functions Φj(y, ψ, τ, ε), j ≥ 0, are continuously differentiable with respect
to y, ψ, and τ for every fixed ε from set (19.1) and satisfy Eq. (18.14). Since
Δ and T are arbitrary, equality (18.14) holds for all (y, ψ, τ, ε) ∈ G, and the
functions Φj(y, ψ, τ, ε) have continuous partial derivatives of the first order with
respect to (y, ψ, τ) ∈ Ph × Rm × R for every ε ∈ (0, ε0].
We now prove that the matrices
∂
∂y
Φj(y, ψ, τ, ε) and
∂
∂ψ
Φj(y, ψ, τ, ε) satisfy
the Lipschitz condition with respect to the variables y and ψ. Using Lemma
18.4 for j = 0 and the inequalities
_ψξ
τ (ψ, ε) − ψξ
τ (ψ, ε)_ ≤ [1 + c4εα(1 + ξ − τ )ec4εα(ξ−τ)]_ψ − ψ_,
_yξ,j
τ (y, ψ, ε) − yξ,j
τ (y, ψ, ε)_
≤ Ke
−γ1(ξ−τ)]_y − y_ + c5h(1 + hd3)e
−γ2(ξ−τ)_ψ − ψ_, ξ≥ τ, (19.3)
222 Integral Manifolds Chapter 3
which follow from relations (18.22) and (18.23) and Lemma 18.2, we deduce the
following estimate from (18.11):
___
∂
∂y
Φ1(y, ψ, τ, ε) − ∂
∂y
Φ1(y, ψ, τ, ε)
___
≤ Knc1
_ c6
γ3
+ n
2γ1
K + nc5h
1
γ1 + γ2
(1 + hd3)
+ (m + nc1εα0
)
_ 1
γ2
+
4
4γ2 − γ1
__
(_y − y_ + _ψ − ψ_)
≤ μ(_y − y_ + _ψ − ψ_).
Here, μ > 0 is a constant, which will be fixed in what follows. Assume that
inequalities (18.25) are satisfied for all j = 1, s, s > 1. Then
___
∂
∂y
Φs+1(y, ψ, τ, ε) − ∂
∂y
Φs+1(y, ψ, τ, ε)
___
≤ c1(n + d2(n + m))
∞ _
τ
___
∂
∂y
yξ,s
τ (y, ψ, ε) − ∂
∂y
yξ,s
τ (y, ψ, ε)
__ _
dξ
+
_
c1(1 + d2 + d3h)K[(1 + d2)(n + m)2 + nd2]
+
_
nc1c1εα0
+ sup
G
___
∂b
∂ϕ
___
_
Kμ
_ ∞ _
τ
(_yξ,s
τ (y, ψ, ε) − yξ,s
τ (y, ψ, ε)_
+ _ψξ
τ (ψ, ε) − ψξ
τ (ψ, ε)_)e
−γ1(ξ−τ)dξ.
Choosing h > 0 and ε0 > 0 so small that hμ ≤ 1 and εα0
μ ≤ 1 and using
Lemma 18.4 and estimates (19.3), we get
___
∂
∂y
Φs+1(y, ψ, τ, ε) − ∂
∂y
Φs+1(y, ψ, τ, ε)
___
≤ c11(_y − y_ + _ψ − ψ_) + sup
G
___
∂b
∂ϕ
___
1
2γ1
K2μ_y − y_
+ sup
G
___
∂b
∂ϕ
___
1
γ1
Kμ_ψ − ψ_, (19.4)
Section 19 Proof of Theorem 18.1 223
where
c11 = c1[n + d2(n + m)]
2
γ3
c6
+ c1K[(2 + d2)(nd2 + (1 + d2)(n + m)2 + nc1)]
_ 2c5
(γ1 + γ2)d3
+ K
2γ1
_
+ mc1K
_ 2c5
γ1 + γ2
+
4
9γ2
1
c4(4 + 3γ1)
_
.
Since γ1 >
1
2γ and, according to condition (18.15), the constant
σ0 = K
γ
sup
G
___
∂b
∂ϕ
___
max{2;K}
is less than 1, it follows from inequality (19.4) that
___
∂
∂y
Φs+1(y, ψ, τ, ε) − ∂
∂y
Φs+1(y, ψ, τ, ε)
___
≤ (c11 + μσ0)(_y − y_ + _ψ − ψ_) ≤ μ(_y − y_ + _ψ − ψ_),
μ = c11
1 − σ0
.
Thus, we have established inequalities (18.25) for all j ≥ 0.
By analogy, using Lemma 18.5, for sufficiently small h > 0 and ε0 > 0 one
can prove inequalities (18.26) for all j ≥ 0 with the constant ν independent of
ε and h.
Consider the problem of the convergence of the sequence {Φj(y, ψ, τ, ε)} on
the set G. In view of inequalities (18.27) and (18.31), relation (18.11) yields
_Φj+1(y, ψ, τ, ε) − Φj(y, ψ, τ, ε)_
≤
_
(n + (m + nc1εα0
)d2) c1
γ5
_y_2 + sup
G
___
∂b
∂ϕ
___
1
γ1
K_y_
_
sup
G
vj−1
or
sup
G
vj ≤
_
σ0 + c1(n + m)d2
1
γ5
h
_
sup
G
vj−1. (19.5)
For small h > 0, the expression in the square brackets on the right-hand side of
inequality (19.5) can be estimated by a constant c12 less than 1. Consequently,
the inequalities
224 Integral Manifolds Chapter 3
sup
G
vj ≤ c12 sup
G
vj−1, c12 < 1, sup
G
v0 ≤ d1
imply that the numerical series
∞,
j=0
sup
G
vj is convergent, and, hence, the functional
sequence {Φj(y, ψ, τ, ε)} converges uniformly on the set G to the limit
function
Φ(y, ψ, τ, ε) = lim
j→∞
Φj(y, ψ, τ, ε)
continuous in y, ψ, and τ.
By analogy, using estimates (18.28) and (18.29) we prove the uniform convergence
of the sequences
_ ∂
∂ψ
Φj(y, ψ, τ, ε)
_
and
_ ∂
∂y
Φj(y, ψ, τ, ε)
_
on the
set G.
Consider the sequence
_ ∂
∂τ
Φj(y, ψ, τ, ε)
_
each element of which is determined
by equality (18.14). The smoothness conditions for the right-hand side of
system (18.1) and the uniform convergence of the sequences {Φj},
_ ∂
∂ψ
Φj
_
,
and
_ ∂
∂y
Φj
_
on the set G yield the uniform convergence of the sequence
_ ∂
∂τ
Φj
_
on set (19.1). Therefore, the limit function Φ(y, ψ, τ, ε) is continuous
in y, ψ, and τ for every fixed ε from set (19.1). Passing to the limit as
j → ∞ in Eq. (18.4), we obtain Eq. (18.10) for all y, ψ, τ, and ε from set
(19.1). Since T and Δ are arbitrary, we get Eq. (18.10) for any (y, ψ, τ, ε) ∈ G.
The Lipschitz conditions (18.17) follow from inequalities (18.25) and (18.26).
Theorem 18.1 is proved.
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