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6.6 Membranes
Tents or similar space-like membranes can be analyzed with special flat elements
by combining the structural behavior of a prestressed membrane with
a rigid cloth.
If it is assumed that the horizontal prestressing force H in the membrane
is uniform in all directions, the deflection of the membrane satisfies the differential
equation
− H (w,xx +w,yy ) =p p= wind pressure . (6.45)
As expected, this is the extension to 2-D problems of the one-dimensional
equation −Hw__ = p of a taut rope. If the model is extended and it is assumed
that the prestressing force in the x-direction Hx is different from the force Hy
in the y-direction, then it seems reasonable to modify the differential equation
as follows
− Hx w,xx −Hy w,yy = p . (6.46)
Green’s first identity for this equation is
G(w, ˆ w) =
_
Ω
(−Hx w,xx −Hy w,yy ) ˆ wdΩ (6.47)
+
_
Γ
(Hx w,x nx + Hy w,y ny) ˆ wds − a(w, ˆ w) = 0, (6.48)
where the strain energy product is
a(w, ˆ w) =
_
Ω
(Hx w,x ˆ w,x +Hy w,y ˆ w,y ) dΩ . (6.49)
To understand how the analysis proceeds, let us consider a bar element.
6.6 Membranes 499
Fig. 6.14. Rotation of a bar element
Originally the stiffness matrix of the bar element is a 2 × 2-matrix, which
is enlarged to a 4 × 4-matrix to account for possible rotations of the element
(see Fig. 6.14):
EA
le
_
1 −1
−1 1
_ _
u1
u2
_
⇒ EA
le
⎡
⎢⎢⎣
1 0 −1 0
0 0 0 0
−1 0 1 0
0 0 0 0
⎤
⎥⎥⎦
⎡
⎢⎢⎣
u1
u2
u3
u4
⎤
⎥⎥⎦
. (6.50)
Assuming that the bar element is stabilized by a horizontal force H, we obtain
Ku =
⎧⎪⎪⎨
⎪⎪⎩
EA
le
⎡
⎢⎢⎣
1 0 −1 0
0 0 0 0
−1 0 1 0
0 0 0 0
⎤
⎥⎥⎦
+ H
le
⎡
⎢⎢⎣
0 0 0 0
0 1 0 −1
0 0 0 0
0 −1 0 1
⎤
⎥⎥⎦
⎫⎪⎪⎬
⎪⎪⎭
⎡
⎢⎢⎣
u1
u2
u3
u4
⎤
⎥⎥⎦
= f .
(6.51)
The horizontal force H adds vertical stiffness to the bar, because the force H
tends to pull the bar straight.
The structure of this matrix resembles the stiffness matrix of a beam in
second-order beam theory. The first part is the linear stiffness matrix, and the
second is the so-called geometric stiffness matrix, which is just the stiffness
matrix of the rope,
H
le
_
1 −1
−1 1
__
u1
u2
_
=
_
f1
f2
_
, (6.52)
extended to 4×4. Hence the stiffness matrix of a membrane element consists
of the stiffness matrix KS of the cloth (orthotropic material) and a membrane
matrix KM:
K = KS +KM . (6.53)
An appropriate choice for the membrane part is the rectangular Q4+2 element,
and to these four bilinear shape functions are added the unit deflections
500 6 Shells
Fig. 6.15. Roofing of sand boxes with a prestressed membrane: a) system,
b) deformations due to gravity load + live load + snow
of the four nodes, so that the membrane matrixKM contains the strain energy
kM
ij =
_
Ω
(Hx ϕi,x ϕj ,x +Hy ϕi,y ϕj ,y ) dΩ . (6.54)
Hence, a prestressed membrane is analyzed in two steps: first the shape is
found, then the stresses are calculated.
In the first step only the geometric matrix due to the prestressing forces is
activated. In other words, in this step the extensional stiffness is assumed to be
zero. To prevent the nodes from swimming on the surface of the membrane, as
if on a soap film, the nodes are stabilized in the tangential direction by small
springs. In the second step the stresses within the membrane are calculated.
Figure 6.16 a illustrates finding the shape of a tightly stressed rope. The
deflection of nodes 1 and 4 is given: u1 = 1.0 m, u4 = 1.4 m. The unknowns are
the associated nodal forces f1, f4 and displacements u2, u3 of the free nodes,
so that the system for the unknowns is
found, then the stresses are calculated; see Fig. 6.15.
6.6 Membranes 501
Fig. 6.16. Determining the shape a) of a taut rope, and b) of a membrane
Fig. 6.17. Determining the shape of a membrane supported along its edge:
H
le
⎡
⎢⎢⎣
2 −1 0 0
−1 2−1 0
0 −1 2−1
0 0−1 2
⎤
⎥⎥⎦
=
⎡
⎢⎢⎣
1.0
u2
u3
1.4
⎤
⎥⎥⎦
=
⎡
⎢⎢⎣
f100
f4
⎤
⎥⎥⎦
. (6.55)
The starting point for finding the shape of a membrane can either be a
3-D system (see Fig. 6.17) or a plane system. If the analysis starts with a
3-D shape, the individual elements are initially flat. If it starts with a plane
a) starting position, b) final shape
502 6 Shells
Fig. 6.18. Wind load: a) undeformed system, b) deformations due to wind load;
(the maximum deflection at the center of the membrane was about 30 cm)
Fig. 6.19. Wind load a) undeformed system b) deformations under wind load, the
maximum deflection at the center of the membrane was about 30 cm
system as in Fig. 6.16 b, the edge of the membrane is moored at the supports
and pulled upwards.
Once the shape has been found, the stresses resulting from wind loads and
snow must be determined. While snow is a simple load case, the wind load
depends on the height, position and orientation of the individual elements; see
Figs. 6.18 and 6.19. Under the action of high wind pressure, the magnitude of
the tensile stresses from the prestressing forces may not be great enough and
wrinkles will develop in the membrane. Because the full wind load does not
converge in one step, the wind load must be applied in single steps instead.
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