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7.2 Green’s identities
’The principle of virtual displacements is nothing else than integration by
parts’ and so we start this section with repeating the rules for integration by
parts before we formulate Green’s identities which are based on integration
by parts. These identities encapsulate the basic principles of mechanics and
play a fundamental role in finite element analysis.
Integration by parts
Let u and ˆu be two functions with continuous first derivatives in the interval
(0, l) then
_ l
0
u
_ ˆudx = [u ˆu] l
0
−
_ l
0
u ˆu
_
dx (7.39)
and in higher dimensions with functions u and ˆu from C1(Ω),
_
Ω
u,xi ˆudΩ =
_
Γ
uni ˆuds −
_
Ω
u ˆu,xi dΩ , (7.40)
where ni is the i-th component of the normal vector n on the edge Γ of the
domain Ω.
For example let ˆu = 1 and u_ = ε the strain in a rod then
_ l
0
ε dx = u(l) − u(0) . (7.41)
In a plate where εxx = ux,x the same statement is
_
Ω
εxx dΩ =
_
Γ
ux nx ds . (7.42)
If for example Ω = a×b is a rectangle with nx = ±1 on the vertical edges ΓL
and ΓR and nx = 0 on the horizontal edges then the result resembles the 1-D
result
_
Ω
εxx dΩ =
_
ΓR
ux ds −
_
ΓL
ux ds . (7.43)
7.2 Green’s identities 509
of a bar element dN+pdx = 0
Bars
The equilibrium condition
_
H = 0 for a bar element dx (see Figure 7.1)
leads to the differential equation
− EAu
__ = p , (7.44)
where u(x) is the longitudinal displacement, p is the applied load, and EA
is the (constant) stiffness of the bar. If the left-hand side of the differential
equation is multiplied by a virtual displacement δu and we integrate by parts
_ l
0
−EAu
__
δu dx = [−EAu
_
δu] l
0
−
_ l
0
−EAu
_
δu
_
dx , (7.45)
the result is Green’s first identity:
G(u, δu) =
_ l
0
−EAu
__
δu dx
_ _ _
start
+[N δu] l
0
−
_ l
0
EAu
_
δu
_
dx
_ _ _
transformed terms
=
_ l
0
−EAu
__
δu dx + [N δu] l
0
_ _ _
δWe
−
_ l
0
EAu
_
δu
_
dx
_ _ _
δWi
= 0. (7.46)
The terms in brackets
[N δu]l
0 = N(l) δu(l) − N(0) δu(0) (7.47)
are the virtual external work done by the normal forces N = EAu_ at the
ends of the bar.
The expression B(u, ˆu) = G(u, ˆu) − G(ˆu, u) = 0 − 0 = 0 is Green’s second
identity,
B(u, ˆu) =
_ l
0
−EAu
__ ˆudx + [N ˆu] l
0
_ _ _
W1,2
−[u ˆN ] l
0
−
_ l
0
u (−EA ˆu
__) dx
_ _ _
W2,1
= 0
(7, .48)
and it formulates Betti’s theorem.
Fig. 7.1. Static equilibrium
510 7 Theoretical details
Fig. 7.2. Archimedes’ dilemma: all effort is consumed by the strain energy a) the
Earth will not move one iota b) the rubber band will stretch and stretch and ...
Green’s first identity basically is of the form
G(u, ˆu) = p(ˆu) − a(u, ˆu) = δWe(u, ˆu) − δWi(u, ˆu) = 0 (7.49)
or if it is solved for the strain energy product
a(u, ˆu) = p(ˆu) . (7.50)
Note that a(u, ˆu) is the first-order derivative of the quadratic form
F(u) =
1
2 a(u, u) , (7.51)
that is
F
_(u) :=
_
d
dε
1
2 a(u + εˆu, u + εˆu)
_
ε=0
= a(u, ˆu) . (7.52)
Beam
The differential equation of a beam with constant bending stiffness EI is
EI wIV (x) = p(x) . (7.53)
The bending moment is M(x) = −EI w__(x) and the shear force is V (x) =
−EI w___(x). Green’s first identity for the beam equation is
G(w, ˆ w) =
_ l
0
EI wIV ˆ wdx + [V ˆ w −M ˆ w
_] l
0
_ _ _
δWe
−
_ l
0
M ˆM
EI
dx
_ _ _
δWi
= 0, (7.54)
and B(w, ˆ w) = G(w, ˆ w) − G( ˆ w,w) = 0 is Betti’s theorem.
7.2 Green’s identities 511
An application—Archimedes’ dilemma
A place to stand does not suffice to move the Earth. Archimedes needs also a
lever with EI = ∞; see Fig. 7.2 a. Otherwise the lever will only bend. Because
of Green’s first identity G(w,w) = We − Wi = 0 the exterior work is at any
moment equal to the strain energy in the beam
We = Pr · wr − Pl · wl = a(w,w) =
_ l
0
M2
EI
dx = Wi (7.55)
or
Pr · wr = Pl · wl + a(w,w) . (7.56)
So that all of Archimedes’ effort, Pr · wr, will be consumed by the internal
energy a(w,w) and very little—effectively nothing—remains to lift the Earth.
The same happens if you try to pull a heavy weight across the wet sand
on the beach (see Fig. 7.2 b)
We = Pr · _ _u_r
your effort
−Pl · ul = a(u, u) =
_ l
0
N2
EA
dx = Wi . (7.57)
The rubber band (EA) will stretch and stretch and stretch, ur → 1, 2, 3, . . .,
that is a(u, u) will increase but the weight will hardly move, ul _ 0.
Poisson equation
Green’s first identity for the differential equation −Δu = p is
G(u, ˆu) =
_
Ω
−Δu ˆudΩ +
_
Γ
∂u
∂n
ˆuds
_ _ _
δWe
−
_
Ω
∇u •∇ˆudΩ
_ _ _
δWi
= 0, (7.58)
where
a(u, ˆu) =
_
Ω
∇u •∇ˆudΩ =
_
Ω
(u,x ˆu,x +u,y ˆu,y ) dΩ (7.59)
is the strain energy product.
Kirchhoff plate
The differential equation of the Kirchhoff plate is the biharmonic equation
KΔΔw =p K= E h3
12 (1 − ν2) . (7.60)
512 7 Theoretical details
The curvature tensor K = [κij ] has elements κij = w,ij , and the bending
moment tensor is M = K {(1 − ν)K + ν(trK) I}, or
mxx = −K (w,xx +ν w,yy ), myy = −K (w,yy +ν w,xx ) , (7.61)
mxy = −(1 − ν)Kw,xy . (7.62)
The shear forces are
qx = −K (w,xxx +w,yyx ) qy = −K (w,xxy +w,yyy ) , (7.63)
and the resultant stresses on the boundary are, in indicial notation,
mn = mij ni nj mnt = mij ni tj (7.64)
qn = qi ni vn = d
ds
mnt + qn . (7.65)
Green’s first identity is
G(w, ˆ w) =
_
Ω
KΔΔw ˆ wdΩ +
_
Γ
[vn ˆ w − mn ˆ w,n ] ds +
_
i
Fi ˆ w(xi)
_ _ _
δWe
− a(w, ˆ w)
_ _ _
δWi
= 0, (7.66)
where the strain energy product is the expression
a(w, ˆ w) =
_
Ω
[w,xx ( ˆ w,xx +ν ˆ w,yy ) + 2(1 − ν) w,xy ˆ w,xy
+w,yy ( ˆ w,yy +ν ˆ w,xx )] dΩ =
_
Ω
M• ˆK dΩ (7.67)
and the Fi are the corner forces resulting from the jumps in the twisting
moment mnt:
Fi := F(w)(xi) = mnt(x+
i ) − mnt(x
−
i ) . (7.68)
Reissner–Mindlin plate
The terms of a Reissner–Mindlin plate are the rotations ϕ = [ϕx, ϕy]T, the
deflection w, the shearing strains γ = [γx, γy]T , the curvature tensor K, the
bending moment tensor M, and the shear forces q = [qx, qy]T which are
governed by the equations
strains: K(ϕ) −K = 0 ϕ + ∇w − γ = 0 (7.69)
material law: C[K] −M = 0 a γ − q = 0 (7.70)
equilibrium: −divM + q = b∇p −div q = p (7.71)
7.2 Green’s identities 513
where
K(ϕ) =
1
2
(∇ϕ + ∇ϕT) =
1
2
_
2 ϕx,x ϕx,y +ϕy,x
ϕy,x +ϕx,y 2 ϕy,y
_
(7.72)
C[K] = K (1 − ν)E +ν K (trK) I (7.73)
and
K = E h3
12 (1 − ν2), a= K
1 − ν
2
 ̄λ
2, b= ν
1 − ν
1
 ̄λ
2
, λ ̄2 =
10
h2 , (7.74)
where h is the plate thickness. These equations are equivalent to the system
− divC[K(ϕ)] + a(ϕ + ∇w) = b∇p (7.75)
−div (a (ϕ + ∇w)) = p (7.76)
or in indicial notation
− mαβ,β +a qα = b p,α, α= 1, 2 (7.77)
−a qβ,β = p (7.78)
where
mαβ = K(1 − ν)
1
2
(ϕα,β +ϕβ,α ) +ν K ϕγ,γ δαβ (7.79)
qα = ϕα + w,α . (7.80)
If this system is interpreted as the application of an operator −L to the
vector-valued function u = [ϕx, ϕy, w]T we have the identity
G(u,ˆu) =
_
Ω
−Lu•ˆu dΩ +
_
Γ
[Mn•ˆϕ + q •n ˆ w ] ds − a(u,ˆu) = 0
(7.81)
where
a(u,ˆu) =
_
Ω
[M• ˆK + q •ˆγ ] dΩ . (7.82)
Linear elasticity
The governing equation is
Lu := −
_
μΔ+ μ
1 − 2 ν
∇div
_
u = p , (7.83)
or in tensor notation
514 7 Theoretical details
separately on each element
− μui,jj − μ
1 − 2 ν
uj ,ji = pi i = 1, 2 (7.84)
which is equivalent to
− σij ,j = pi i = 1, 2 . (7.85)
Green’s first identity is
G(u,ˆu) =
_
Ω
−Lu•ˆu dΩ +
_
Γ
τ (u) •ˆu dΩ − a(u,ˆu) = 0, (7.86)
where τ (u) = Sn is the traction vector on the boundary and
a(u,ˆu) =
_
Ω
[σxx ˆεxx + 2σxy ˆεxy + σyy ˆεyy] dΩ =
_
Ω
S • ˆE dΩ (7.87)
is the strain energy product. For more identities see [115].
Regularity
Because the identities are based on integration by parts, the functions u and
ˆu must be sufficiently regular. If that is not the case, the interval (0, l) or the
domain Ω can be subdivided into as many intervals or partitions as necessary:
G(u, ˆu)(0,l) = G(u, ˆu)(0,l1) + G(u, ˆu)(l1,l2) + . . . + G(u, ˆu)(ln,l) = 0.
(7.88)
Typically the partitions are the individual elements; see Fig. 7.3.
Green’s first identity and stiffness matrices
Substituting two nodal unit displacements (not necessarily the actual displacements
but “any” displacements ϕi) into Green’s first identity for a beam
yields
G(ϕi, ϕj) =
_ l
0
EIϕIV
i ϕj dx +
_
Vi ϕj −Mi ϕ
_
j
_l
0
_ _ _
p ij
−
_ l
0
EIϕ
__
i ϕ
__
j dx
_ _ _
k ij
= 0
(7.89)
Fig. 7.3. Problems of regularity
can be overcome by
formulating Green’s identity
7.2 Green’s identities 515
which means that
δWe(pi, ϕj) = p ij = k ij = δWi(ϕi, ϕj) (7.90)
or that the strain energy product (virtual internal energy) k ij between two
such nodal unit displacements ϕi and ϕj is equal to the virtual external work
p ij done by the unit load case pi via the virtual displacements ϕj .
The load case pi simply consists of all forces that produce the shape ϕi, i.e.,
the distributed load EI ϕIV
i , the shear forces Vi(0), Vi(l), and the moments
Mi(0),Mi(l) at the ends of the beam. The double subscripted term p ij is the
virtual external work δWe(pi, ϕj) corresponding to the load case pi and the
virtual displacement ϕj .
With uh =
_
j uj ϕj and the n-fold identity
G(uh, ϕi) = 0 i = 1, 2, . . . n (7.91)
this is equivalent to
P u−Ku = 0 or fh
−Ku = 0 (7.92)
where fh := P u.
Strain energy = nodal forces × nodal displacements
It should be obvious by now that the strain energy in a single element
a(uh,uh)Ωe =
_
Ωe
σij · εij dΩ =
_
Ωe
ph
•uh dΩ +
_
Γe
th •uh ds = fTe
ue
(7.93)
is the same as the scalar product between the equivalent nodal forces of that
element
fe
i =
_
Ωe
ph
•ϕei
dΩ +
_
Γe
th •ϕei
ds (7.94)
—the th are the tractions on the edge of the element—and the vector ue of
nodal displacements. Summing the contributions from all elements we obtain
the well known formula for the strain energy stored in a structure
a(uh,uh) = uT Ku = fT u. (7.95)
Green’s first identity and projections
The FE solution uh is the projection of the exact solution u onto Vh
uh ∈ Vh : a(u − uh, ϕi) = 0 ϕi ∈ Vh (7.96)
516 7 Theoretical details
or
uh ∈ Vh : a(uh, ϕi) = a(u, ϕi) = δWe(u, ϕi) = fi ϕi ∈ Vh (7.97)
where δWe(u, ϕi) is short for
G(u, ϕi) =
_ l
0
−EAu
__
ϕi dx + [N ϕi]l
0
_ _ _
δWe(u,ϕi)
−a(u, ϕi) = 0 (7.98)
so that Green’s first identity allows to replace the term a(u, ϕi) by an expression
of external virtual work. This is the vector f.
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