7.3 Green’s functions

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To solve the equation

3 · x = 12 ⇒ x =

1

3

· 12 (7.99)

the right-hand side is multiplied by the “Green’s function” xG = 1/3, which

is the solution of 3 · x = 1.

The Green’s functions are the solutions of the adjoint equations. Consider

for example the system Ku = f and the identity

B(uu) = ˆuT KuuT KT ˆu = 0, (7.100)

where KT is the adjoint (= transpose) of the matrix K. Clearly if gi is a

solution of KT gi = ei then ui = gTi

f.

In linear structural mechanics the equations are self-adjoint (or symmetric

K = KT ) so that the Green’s functions are the solutions of the same

equations, EI GIV

0 = δ0, as in the original problem, EI wIV = p.

The complement of the Green’s function is Green’s second identity (Betti’s

theorem), which in the case of the Laplacian reads

B(u, ˆu) =

_

Ω

Δu ˆudΩ +

_

Γ

∂u

∂n

ˆuds −

_

Γ

u

∂ˆu

∂n

ds −

_

Ω

u (−Δˆu) dΩ = 0.

(7.101)

From this equation we can see what boundary conditions must be imposed on

the Green’s functions; see Fig. 7.4. In a Dirichlet problem

Δu = p , u = g on Γ (7.102)

things are easy:

ΔG0 = δ0, G0 = 0 on Γ (7.103)

7.3 Greens functions 517

Fig. 7.4. Influence function for a beam: a) when a support is displaced, b) Greens

function, c) theoretically no Greens function exists for a beam with no supports

and so

u =

_

Ω

G0 pdΩy

_

Γ

∂G0

∂ n

g ds. (7.104)

In a mixed problem

Δu = p , u = g on ΓD ,

∂u

∂n

= t on ΓN (7.105)

we require that

ΔG0 = δ0, G0 = 0 on ΓD ,

∂G0

∂n

= 0 on ΓN (7.106)

and so

u =

_

Ω

G0 pdΩy

_

ΓD

∂G0

∂ n

g ds +

_

ΓN

G0 t ds . (7.107)

The support conditions of the beam in Fig. 7.4 a are of such a mixed type,

because geometric, w(0) = w_(0) = w(l), as well as static boundary conditions,

M(l) = 0, are prescribed. Hence if the Green’s function of the beam in Fig.

7.4 a solves the boundary value problem

EI GIV

0 = δ0(y − x), G0(0) = G0(l) = G

_

0(0) = −EI G

__

0 (l) = 0,(7.108)

then Betti’s theorem yields

518 7 Theoretical details

B(w,G0) =

_ l

0

pG0 dy + [V G0 −MG

_

0]l

0

− [V0 w −M0 w

_]l

0

_ l

0

wδ0 dy =

_ l

0

p G0 dy + B0(x) δ − w(x) = 0 (7.109)

where −V0(l)w(l) = B0(x) δ with the sign convention in Fig. 7.4.

But influence functions for the solution of Neumann problems do not exist,

because one cannot place a force δ0 on Ω and require at the same time that

all the tractions on the boundary vanish

ΔG0 = δ0

∂G0

∂n

= 0 on Γ ? (7.110)

The reason is that the solution of a Neumann problem is only unique up to a

constant uc as for example in the case of the beam in Fig. 7.4 c, that gives the

impression of a beam on an elastic foundation, EIwIV + cw = p, but it is a

standard beam EIwIV . It is only that the sum of the distributed load on both

sides of the beam happens to be the same, so that no supports are necessary.

Of course Green’s functions for beams on an elastic foundation exist.

Naturally all these problems go away if the solution is made unique by

specifying single values of the solution as w(0) = w(l) = 0, or in terms of

structural mechanics, by adding supports to a structure.

Elastic supports

To be complete let us also discuss the case that the structure rests on an

elastic support. Imagine that the hinged support in Fig. 7.4 is replaced by

a spring with stiffness k. The decisive term in Betti’s theorem (7.109) is the

work term

V0(l)w(l) = kG0(l, x)w(l) = G0(l, x) Vp =

1

k

V0 Vp (7.111)

which encapsulates the interaction between the compression G0(l, x) of the

spring due to the point load P = 1 and the support reaction Vp in the load

case p or—vice versa—the interaction between the support reaction V0 due

to P = 1 and the compression w(l) of the spring in the load case p, so that

the influence function becomes

w(x) =

_ l

0

G0(y, x) p(y) dy + V0(l)w(l) (7.112)

which for the special case w(l) = δ is identical with (7.109). Note that

V0(l)w(l) comes from the “boundary integral” [...]. Such edge contributions

always appear in the influence functions if the structure rests on soft supports.

7.4 Generalized Greens functions 519