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2A.6 The s-Plane
We have noted that the Laplace variable s is a complex variable, with a real part and an imaginary part.
Hence, to represent it we will need two axes at right angles to each other—the real axis and the imaginary
axis. These two axes form a plane, which is called the s-plane. Any general value of s (or any variation or
trace of s) may be marked on the s-plane.
2A.6.1 An Interpretation of Laplace and Fourier Transforms
In the Laplace transformation of a function, f ðtÞ; we multiply the function by e2st and integrate with
respect to t. This process may be interpreted as determining the “components” FðsÞ of f ðtÞ in the
“direction” e2st ; where s is a complex variable. All such components FðsÞ should be equivalent to the
original function, f ðtÞ:
In the Fourier transformation of f ðtÞ we multiply it by e2jvt and integrate with respect to t.
This is the same as setting s ¼ jv: Hence, the Fourier transform of f ðtÞ is FðjvÞ: Furthermore, FðjvÞ
represents the components of f ðtÞ that are in the direction of e2jvt : Since e2jvt ¼ cos vt 2 j sin vt; in
the Fourier transformation we determine the sinusoidal components of frequency v, of a time
Frequency-Domain Analysis 2-51
© 2005 by Taylor & Francis Group, LLC
function f ðtÞ: Since s is complex, FðsÞ is also complex and so is Fð jvÞ: Hence, they all will have a real part
and an imaginary part.
2A.6.2 Application in Circuit Analysis
The fact that sin vt and cos vt are 908 out of phase is further confirmed in view of
ejvt ¼ cos vt þ j sin vt ð2A:21Þ
Consider the R– L – C circuit shown in Figure 2A.2. For the capacitor, the current, i, and the voltage, v, are
related through
i ¼ C
dv
dt ð2A:22Þ
If the voltage v ¼ v0 sin vt; the current i ¼ v0vC cos vt: Note that the magnitude of v=i is 1=vC
(or 1=2p fC where v ¼ 2p f ; f is the cyclic frequency and v is the angular frequency). But v and i are out
of phase by 908. In fact, in the case of a capacitor, i leads v by 908. The equivalent circuit resistance of
a capacitance is called reactance, and is given by
XC ¼
1
2p fC ð2A:23Þ
¼
1
vC ð2A:24Þ
Note that this parameter changes with the frequency.
We cannot add the reactance of the capacitor and the resistance of the resistor algebraically; we must
add them vectorially because the voltages across a capacitor and resistor in series are not in phase, unlike
in the case of a resistor. Also, the resistance in a resistor does not change with frequency. In a series circuit,
as in Figure 2A.2, the current is identical in each element, but the voltages differ in both amplitude and
phase; in a parallel circuit, the voltages are identical, but the currents differ in amplitude and phase.
Similarly, for an inductor,
v ¼ L
di
dt ð2A:25Þ
The corresponding reactance is
XL ¼ vL ¼ 2p f L ð2A:26Þ
If the voltage (E) across R in Figure 2A.2(a) is in the direction shown in Figure 2A.2(b) (i.e., pointing to
the right), then the voltage across the inductor, L, must point up (908 leading) and the voltage across the
capacitor, C, must point down (908 lagging). Since the current (I) is identical in each component of a
E
R
L
C
(a)
EL or IXL
ER or IR
EC or IXC
XL − XC
R
q
Z
(b)
(c)
FIGURE 2A.2 (a) Series RLC circuit; (b) phases of voltage drops; (c) impedance triangle.
2-52 Vibration and Shock Handbook
© 2005 by Taylor & Francis Group, LLC
series circuit, we see the directions of IR, IXL and IXC as in Figure 2A.2(b), giving the impedance triangle
shown in Figure 2A.2(c).
To express these reactances in the s-domain, we simply substitute s for jv :
2jXC ¼
1
sC
jXL ¼ sL
The series impedance of the RLC circuit can be expressed as
Z ¼ R þ jXL 2 jXC ¼ R þ sL þ
1
sC
In this discussion, note the use of
ffiffiffiffi
21 p or j to indicate a 908 phase change.
Frequency-Domain Analysis 2-53
© 2005 by Taylor & Francis Group, LLC
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