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6.3 Isotropic Hyperelasticity with a von Mises–type Yield Surface
6.3.1 Uncoupled isotropic hyperelastic model
Next, the attention is focused on an isotropic hyperelastic model of the form (Simo 1988a)
_(g, be−1, F) = 12
μ(J
−2/3I1be − 3) + U(J) (6.50)
where Ibe is the first invariant of the elastic left Cauchy–Green tensor. The first term on
the right-hand side of Equation (6.50) is isochoric, the second is volumetric. The choice of
U(J) is not unique. Here, we will take
U(J) = 12
K _12
(J 2 − 1) − ln J _ (6.51)
which satisfies the asymptotic requirements
lim
J→+∞
U(J) = +∞ (6.52)
lim
J→0
U(J) = +∞ (6.53)
discussed in Chapter 4. The parameter K is the bulk modulus.
For C = G, Equation (6.50) leads to the classical isotropic Hooke law. To prove this,
the derivative with respect to C is taken. Using relationships derived in Section 4.4 and
noting that I1b = I1C = I1, one obtains
∂_
∂CKL
= 12
μJ
−2/3 _−13
I1C
−1KL + GKL_ + 14
K _J 2 − 1_C
−1KL (6.54)
and
∂2_
∂CKL∂CMN
= −16
μJ
−2/3C
−1MN _GKL − 13I1C
−1KL_
+ 12
μJ
−2/3 _−13
GMNC
−1KL + 16I1(C
−1KM
C
−1LN + C
−1KN
C
−1LM
)_
+ 14
KJ2C
−1MN
C
−1KL − 18
K(J2 − 1)(C
−1KM
C
−1LN + C
−1KN
C
−1LM
). (6.55)
For C = G, the first and last term drop out and one obtains
4
∂2_
∂CKL∂CMN
C=G
= _K − 23
μ_GKLGMN + μ(GKMGLN + GKNGLM) (6.56)
where K − 23
μ = λ. This is the classical Hooke law for linear isotropic materials.
Using the appropriate push-forward/pull-back pairs, Equation (6.50) can be reformulated
as
_(C,Cp) = 12
μ(J
−2/3TRCp−1 − 3) + U(J) (6.57)
280 FINITE STRAIN ELASTOPLASTICITY
where
TR[·] = [·] : C (6.58)
is the pull-back of the trace operator in spatial coordinates:
tr(be) = be : g = Cp : C =: TR(Cp−1
). (6.59)
Equation (6.57) can also be written as
_(C,Cp) = 12
μ(C : Cp−1 − 3) + U(J). (6.60)
Applying Equations (6.19),(6.42) and (6.44), one obtains for the second Piola–Kirchhoff
stress
S = pJC
−1 + μDEV(C
p−1
) (6.61)
where
p = dU
dJ
= 12
K
J 2 − 1
J
(6.62)
and
C
p−1
:= J
−2/3Cp−1
. (6.63)
Accordingly (Equation (6.38)),
∂2_(C,Cp)
∂C∂Cp
= 1
2
∂S
∂Cp
= μ
2
DEV
_∂C
p−1
∂Cp
_
(6.64)
and
∂2_(C,Cp)
∂C∂Cp : ˙C
p = −μJ
−2/3DEV
_∂Cp−1
∂t
_
. (6.65)
6.3.2 Yield surface and derivation of the flow rule
One of the frequently used forms of the yield surface is due to von Mises:
_(S,C,Q) = DEVS + _23
q1 (6.66)
where q1 is a scalar internal plastic variable satisfying q1 = −h1(α1). The variables q1 and
α1 are spatial quantities. Since C
−1 is a symmetric matrix, one finds
DEV(C
−1) = C
−1 − 13
(C : C
−1)C
−1 = 0 (6.67)
leading to (Equation (6.61))
DEVS = μDEV(C
p−1
). (6.68)
FINITE STRAIN ELASTOPLASTICITY 281
Hence, Equation (6.66) can be rewritten as
_(C,Cp,Q) = μDEV(C
p−1
) − _23
h1(α1). (6.69)
The unit of _ is stress, and in the present chapter we will assume that this is the Kirchhoff
stress. Since (S, τ ) and (C, g) are push-forward/pull-back pairs, one can write
DEVS = _(DEVS)IJ (DEVS)KLCIKCJL (6.70)
= _(devτ)ij (devτ)klgikgjl . (6.71)
For the flow rule (Equation (6.38)), we need the derivative of _ with respect to C. One
can write
∂_
∂C
= ∂DEVS
∂C
(6.72)
= 1
2DEVS
∂
∂C
DEVS2. (6.73)
Furthermore (Equation (6.44)),
∂
∂C
DEVS2 = J
−2/3DEV_ ∂
∂C
DEVS2_
. (6.74)
Now (Equation (6.68)),
∂
∂C
DEVS2 = μ2 ∂
∂C
DEVC
p−12 (6.75)
= μ2 ∂
∂C
_(DEVCp−1
)IJ (DEVCp−1
)KLCIKCJL_ (6.76)
= 2μ2 ∂
∂C
(DEVCp−1
)IJ
(DEVCp−1
)KLCIKCJL
+ 2μ2(DEVCp−1
)IJ (DEVCp−1
)KLCJL. (6.77)
Since
∂
∂C
(DEVCp−1
) = ∂
∂C
_Cp−1 − 13
(C : Cp−1
)C
−1_ (6.78)
= ∂
∂C
_Cp−1 − 13
(C : Cp−1
)C
−1_ (6.79)
= −13
(I : Cp−1
)C
−1 + 13
(C : Cp−1
)I
C
−1 (6.80)
= −13
C
−1 ⊗ Cp−1 + 13
(Cp−1 : C)I
C
−1 (6.81)
where
_I
C
−1_IJKL
:= 12
_(C
−1
)IK(C
−1
)JL + (C
−1
)IL(C
−1
)JK_ (6.82)
282 FINITE STRAIN ELASTOPLASTICITY
and
I := II (6.83)
one obtains
∂
∂C
DEVS2AB
= 23
μ2[
(i)
_ __ _ (Cp−1 : C)I
C
−1 −
(ii)
_ __ _
C
−1 ⊗ Cp−1]IJAB(DEVCp−1
)KLCIKCJL
+ 2μ2(DEVCp−1
)AJ (DEVCp−1
)BLCJL
_ (_ii_i) _
. (6.84)
Substituting Equation (6.84) into
∂_
∂C
= J
−2/3
2DEVSDEV_ ∂
∂C
DEVS2_ (6.85)
one notices that ∂_/∂C consists of three additive terms, each of which will be treated
separately:
1.
DEV J
−2/3μ2
3DEVS(Cp−1 : C)IIJAB
C
−1 CIKCJL(DEVCp−1
)KL
= DEV J
−4/3μ2
3DEVS
12
(Cp−1 : C)(δA
KδB
L
+ δB
KδA
L)(DEVCp−1
)KL (6.86)
= DEV J
−2/3μ
3DEVSTRCp−1
(DEVS)AB (6.87)
= μN (6.88)
where
μ := 13
μJ
−2/3TRCp−1 (6.89)
N := DEVS
DEVS. (6.90)
2.
− DEV J
−2/3
2DEVS
23
μ2 _C
−1 ⊗ Cp−1_IJAB
(DEVCp−1
)KLCIKCJL
= −DEV μ2J
−4/3
DEVS(C
−1)IJ (Cp−1
)ABCIKCJL(DEVCp−1
)KL (6.91)
= −DEV μ2J
−4/3
DEVS(Cp−1
)ABCKL(DEVCp−1
)KL = 0 (6.92)
FINITE STRAIN ELASTOPLASTICITY 283
since
C : (DEVCp−1
) = 0. (6.93)
To obtain Equation (6.93), recall that C
−1 : C = 3 since C is symmetric.
3.
DEV J
−2/3
DEVSμ2(DEVCp−1
)AJ (DEVCp−1
)BLCJL
= DEV μ2
DEVS(DEVC
p−1
)AJ (DEVC
p−1
)BLCJL
(6.94)
= DEV (DEVS)AJ (DEVS)BLCJL
DEVS
(6.95)
= DEVSDEV(N2). (6.96)
Accordingly, Equation (6.38) yields
− ˙ γ
∂_
∂C
= −˙ γμ
N +
DEVS
μ
DEV(N2)
. (6.97)
Equating Equations (6.65) and (6.97) yields the flow rule:
−J
−2/3μDEV
_∂Cp−1
∂t
_
= 2γ˙μ
N +
DEVS
μ
DEV(N2)
. (6.98)
The second term on the right-hand side is much smaller than the first one and is usually
dropped.
For infinitesimal strains and rotations, Equation (6.98) reduces to Equation (5.95). Indeed,
substituting μ yields (neglecting the term with N2)
DEV( ˙C
p−1
) = −2γ˙
3
TR(Cp−1
)N. (6.99)
In the infinitesimal theory, one can write
Cp ≈ I + 2_p (6.100)
Cp−1 ≈ I − 2_p (6.101)
˙C
p−1 ≈ −2˙_p. (6.102)
The field _p is deviatoric, hence,
DEV( ˙C
p−1
) ≈ −2˙_ p (6.103)
TR(Cp−1
) ≈ 3 (6.104)
and Equation (6.99) reduces to
˙_
p = ˙γ n (6.105)
which coincides with Equation (5.95).
284 FINITE STRAIN ELASTOPLASTICITY
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