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3. Algebraic Varieties
An algebraic variety is a ringed space that is locally isomorphic to an affine algebraic
variety, just as a topological manifold is a ringed space that is locally isomorphic to
an open subset of Rn; both are required to satisfy a separation axiom.
Algebraic prevarieties. As motivation, recall the following definitions.
Definition 3.1. (a) A topological manifold is a ringed space (V,OV ) such that V
is Hausdorff and every point of V has an open neighbourhood U for which (U,OV |U)
is isomorphic to the ringed space of continuous functions on an open subset of Rn (cf.
(2.2a)).
(b) A differentiable manifold is a ringed space such that V is Hausdorff and every
point of V has an open neighbourhood U for which (U,OV |U) is isomorphic to a
ringed space as in (2.2b).
(c) A complex manifold is a ringed space such that V is Hausdorff and every point
of V has an open neighbourhood U for which (U,OV |U) is isomorphic to a ringed
space as in (2.2c).
The above definitions are easily seen to be equivalent to the more classical definitions
in terms of charts and atlases. Often one imposes additional conditions on V ,
for example, that it is second countable or connected.
Definition 3.2. An algebraic prevariety is a ringed space (V,OV ) such that V
is quasi-compact and every point of V has an open neighbourhood U such that
(V,OV |U) is an affine algebraic variety.
Equivalently, a ringed space (V,OV ) is an algebraic prevariety if there is a finite
open covering V = ∪Vi such that (Vi,OV |Vi) is an affine algebraic variety for all i.
An algebraic variety will be defined to be an algebraic prevariety satisfying a certain
separation condition.
An open subset U of an algebraic prevariety V such that (U, OV |U) is an affine
algebraic variety is called an open affine (subvariety) in V .
Let (V,OV ) be an algebraic variety, and let U be an open subset of V . The functions
f : U → k lying in Γ(U,OV ) are called regular. Note that if (Ui) is an open covering of
V by affine varieties, then f : U → k is regular if and only if f|Ui ∩U is regular for all
i (this is just a special case of condition (c) to be a sheaf, p12). Thus understanding
the regular functions on open subsets of V amounts to understanding the regular
functions on the open affine subvarieties and how these subvarieties fit together to
form V .
Example 3.3. Any open subset of an affine variety together with its induced
ringed structure is an algebraic prevariety (in fact variety). For example, A2 \{(0, 0)}
is an algebraic variety.
Example 3.4. (Projective space). Let
Pn = kn+1 \ {(0, . . . , 0)}/∼
where (a0, . . . , an) ∼ (b0, . . . , bn) if there is a c ∈ k× such that (a0, . . . , an) =
(cb0, . . . , cbn). Thus the equivalence classes are the lines through the origin in kn+1.
Algebraic Geometry: 3. Algebraic Varieties 45
Write (a0 : . . . : an) for the equivalence class containing (a0, . . . , an). For each i, let
Ui = {(a0 : . . . : ai : . . . : an) ∈ Pn | ai _= 0}.
Then Pn = ∪Ui, and the map ui
(a1, . . . , an) _→ (a0 : . . . : ai−1 : 1 : ai+1, . . . : an) : kn → Ui
is a bijection. We use this map to transfer the Zariski topology on kn to Ui, and we
endow Pn with the topology such that U ⊂ Pn is open if and only if U ∩ Ui is open
in Ui for all i. Define a function f : U → k on an open subset U of Pn to be regular
if f ◦ ui is a regular function on kn for all i. These definitions endow Pn with the
structure of a ringed space, and each map ui is an isomorphism of ringed spaces (An,
OAn) → (Ui, OV |Ui). Thus Pn is an algebraic prevariety. Later (see Section 5), we
shall study Pn in detail.
Regular maps. In each of the examples (3.1a,b,c), a morphism of manifolds (continuous
map, differentiable map, analytic map respectively) is just a morphism of
ringed spaces. This motivates the following definition.
Let (V,OV) and (W,OW) be algebraic prevarieties. A map ϕ: V → W is said to
be regular if it is a morphism of ringed spaces. A composite of regular maps is again
regular (this is a general fact about morphisms of ringed spaces).
Note that we have four categories:
(Affine varieties) ⊂ (Alg. prevarieties) ⊂ (ringed spaces).
Each subcategory is full (i.e., the morphisms Mor(V,W) are the same in the four
categories).
Proposition 3.5. Let (V,OV ) and (W,OW) be prevarieties, and let ϕ: V → W
be a continuous map (of topological spaces). Let W = ∪Wi be a covering of W by
open affines, and let ϕ−1(Wj) = ∪Vji be a covering of ϕ−1(Wj) by open affines. Then
ϕ is regular if and only if its restrictions
ϕ|Vji : Vji → Wj
are regular for all i, j.
Proof. We assume that ϕ satisfies this condition, and prove that it is regular. Let
f be a regular function on an open subset U of W. Then f|U ∩Wj is regular for each
Wj (because the regular functions form a sheaf), and so f ◦ ϕ|ϕ−1(U) ∩ Vji is regular
for each j, i (this is our assumption). It follows that f ◦ ϕ is regular on ϕ−1(U) (sheaf
condition). Thus ϕ is regular. The converse is equally easy.
Aside 3.6. A differentiable manifold of dimension d is locally isomorphic to an
open subset of Rd. In particular, all manifolds of the same dimension are locally
isomorphic. This is not true for algebraic varieties, for two reasons:
(a) We are not assuming our varieties are nonsingular (see the next section).
(b) The inverse function theorem fails in our context. If P is a nonsingular point on
variety of dimension d, we shall see (in the next section) that there is a neighbourhood
U of P and a regular map ϕ: U → Ad such that map (dϕ)P : TP → Tϕ(P) on the
tangent spaces is an isomorphism. If the inverse function theorem were true in our
context, it would tell us that an open neighbourhood of P is isomorphic to an open
neighbourhood of ϕ(P).
46 Algebraic Geometry: 3. Algebraic Varieties
Algebraic varieties. In the study of topological manifolds, the Hausdorff condition
eliminates such bizarre possibilities as the line with the origin doubled, where a
sequence tending to the origin has two limits.
It is not immediately obvious how to impose a separation axiom on our algebraic
varieties, because even affine algebraic varieties are not Hausdorff. The key is to
restate the Hausdorff condition. Intuitively, the significance of this condition is that
it implies that a sequence in the space can have at most one limit. Thus a continuous
map into the space should be determined by its values on a dense subset, i.e., if ϕ
and ψ are continuous maps Z → U that agree on a dense subset of Z then they
should agree on the whole of Z. Equivalently, the set where two continuous maps
ϕ, ψ: Z → U agree should be closed. Surprisingly, affine varieties have this property,
provided ϕ and ψ are required to be regular maps.
Lemma 3.7. Let ϕ and ψ be regular maps of affine algebraic varieties Z ⇒ V .
The subset of Z on which ϕ and ψ agree is closed.
Proof. There are regular functions xi on V such that P _→ (x1(P), . . . , xn(P))
identifies V with a closed subset of An (take the xi to be any set of generators for
k[V ] as a k-algebra). Now xi ◦ ϕ and xi ◦ ϕ are regular functions on Z, and the set
where ϕ and ψ agree is
_n
i=1 V (xi ◦ ϕ − xi ◦ ψ), which is closed.
Definition 3.8. An algebraic prevariety V is said to be separated, or to be an
algebraic variety, if it satisfies the following additional condition:
separation axiom: for every pair of regular maps ϕ, ψ: Z ⇒ V with Z an algebraic
prevariety, the set {z ∈ Z | ϕ(z) = ψ(z)} is closed in Z.
The terminology not completely standardized:o ften one requires a variety to be
irreducible, and sometimes one calls a prevariety a variety.
Remark 3.9. In order to check that a prevariety V is separated, it suffices to
show that for every pair of regular maps ϕ, ψ: Z → V with Z an affine algebraic
variety {z ∈ Z | ϕ(z) = ψ(z)} is closed in Z. To prove this remark, cover Z with
open affines. Thus (3.7) shows that affine varieties are separated.
Example 3.10. (The affine line with the origin doubled.) Let V1 and V2 be copies
of A1. Let V ∗ = V1 # V2 (disjoint union), and give it the obvious topology. Define an
equivalence relation on V ∗ by
x (in V1) ∼ y (in V2) ⇐⇒ x = y and x _= 0.
Let V be the quotient space V = V ∗/∼ with the quotient topology (a set is open if
and only if its inverse image in V ∗ is open). Then V1 and V2 are open subspaces of
V , V = V1 ∪ V2, and V1 ∩ V2 = A1 − {0}. Define a function on an open subset to be
regular if its restriction to each Vi is regular. This makes V into a prevariety, but not
a variety:i t fails the separation axiom because the two maps
A1 = V1 8→ V
∗
, A1 = V2 8→ V
∗
agree exactly on A1 − {0}, which is not closed in A1.
Algebraic Geometry: 3. Algebraic Varieties 47
Subvarieties. Let (V,OV ) be a prevariety. Then V is a finite union of open affines,
and in each open affine the open affines (in fact the basic open subsets) form a basis
for the topology. From this it follows the open affines form a basis for the topology on
V , i.e., every open subset U of V is a union of open affines (of V ). It follows that, for
any open subset U of V , (U,OV |U) is a prevariety. Obviously the inclusion U 8→ V
is regular. A regular map ϕ: W → V is an open immersion if ϕ(W) is open in V and
ϕ defines an isomorphism W → ϕ(W) (of prevarieties).
Any closed subset Z in V has a canonical structure of an algebraic prevariety:
endow it with the induced topology, and say that a function f on an open subset of Z
is regular if each point P in the open subset has an open neighbourhood U in V such
that f extends to a regular function on U. To show that Z, with this ringed space
structure is a prevariety, check that for every open affine U ⊂ V , the ringed space
(U ∩ Z,OZ|U ∩ Z) is isomorphic to U ∩ Z with its ringed space structure acquired as
a closed subset of U (see p45). A regular map ϕ: W → V is a closed immersion if
ϕ(W) is closed in V and ϕ defines an isomorphism W → ϕ(W) (of prevarieties).
A subset W of a topological space V is said to be locally closed if every point P in
W has an open neighbourhood U in V such that W ∩ U is closed in U; equivalently,
W is the intersection of an open and a closed subset of V . A locally closed subset
W of a prevariety V acquires a natural structure as a prevariety:wr ite it as the
intersection W = U ∩ Z of an open and a closed subset; Z is a prevariety, and W
(being open in Z) therefore acquires the structure of a prevariety. This structure
on W has the following characterization:the inclusion map W 8→ V is regular, and
a map ϕ: V _ → W with V _ a prevariety is regular if and only if it is regular when
regarded as a map into V . With this structure, W is called a sub(pre)variety of V .
A morphism ϕ: V _ → V is called an immersion if it induces an isomorphism of V _
onto a subvariety of V . Every immersion is the composite of an open immersion with
a closed immersion (in both orders).
A subprevariety of a variety is automatically separated.
Proposition 3.11. A prevariety V is separated if and only if it has the following
property: if two regular maps ϕ, ψ: Z ⇒ V agree on a dense subset of Z, then they
agree on the whole of Z.
Proof. If V is separated, then the set where ϕ and ψ agree is closed, and so must
be the whole of Z.
Conversely, consider a pair of maps ϕ, ψ: Z ⇒ V , and let S be the subset of Z
on which they agree. We assume V has the property in the statement of the lemma,
and show that S is closed. Let  ̄ S be the closure of S in Z. According to the above
discussion,  ̄ S has the structure of a closed prevariety of Z, and the maps ϕ|  ̄ S and
ψ|  ̄ S are regular. Because they agree on a dense subset of  ̄ S they agree on the whole
of  ̄ S, and so S =  ̄ S is closed.
Prevarieties obtained by patching. Let V = ∪Vi (finite union), and suppose that
each Vi has the structure of an algebraic prevariety satisfying the following condition:
for all i, j, Vi∩Vj is open in both Vi and Vj and the structures of an algebraic prevariety
induced on it by Vi and Vj are equal. Then we can define the structure of a ringed
space on V as follows: U ⊂ V is open if and only if U ∩ Vi is open for all i, and
48 Algebraic Geometry: 3. Algebraic Varieties
f : U → k is regular if and only if f|U ∩ Vi is regular for all i. It is straightforward to
check that this does make V into a ringed space (V,OV ).
Proposition 3.12. The ringed space (V,OV ) is a prevariety, and the inclusions
Vi 8→ V are regular maps.
Proof. One only has to check that the ringed space structure on each Vi induced
by that of V is the original one.
Products of varieties. Let V and W be objects in a category C. A triple
(V × W, p: V ×W → V , q : V ×W → W)
is said to be the product of V and W if, for all objects Z in C, themap ϕ _→ (p◦ϕ, q◦ϕ)
is a bijection
Hom(Z, V ×W) → Hom(Z, V ) × Hom(Z,W),
i.e., if every pair of morphisms Z → V , Z → W factors uniquely through V ×W :
Z
✠_
_
_ ❅
❅
❅❘
V ✛ V ×W
❄
.....
∃!
✲ W.
Clearly, the product, if it exists, is uniquely determined up to a unique isomorphism11.
For example, the product of two sets (in the category of sets) is the usual cartesion
product of the sets, and the product of two topological spaces (in the category of
topological spaces) is the cartesian product of the spaces (as sets) with the usual
product topology.
We shall show that products exist in the category of algebraic varieties. Suppose,
for the moment, that V × W exists. It follows from (2.17b) that for any prevariety
Z, Mor(A0, Z) is the underlying set of Z, i.e., for any z ∈ Z, the map A0 → Z with
image z is regular, and these are all the regular maps. Thus, from the definition of
products we have
(underlying set of V ×W) = Mor(A0, V ×W)
= Mor(A0, V ) × Mor(A0,W)
= (underlying set of V ) × (underlying set of W).
Thus our problem can be restated as follows:g iven two prevarieties V and W, define
on the set V ×W the structure of a prevariety such that the projection maps p, q : V ×
W ⇒ V,W are regular, and such that a map ϕ: T → V × W of sets (with T an
algebraic prevariety) is regular if and only if its components p ◦ ϕ, q ◦ ϕ are regular.
Clearly, there can be at most one such structure on the set V × W (because the
identity map will identify any two structures having these properties).
11If (P, p_ : P → V, q_ : P → W) also has this property, then there exists a unique morphism
γ : P → V ×W such that p ◦ γ = p_ and q ◦ γ = q_ (universal property of V ×W), and there exists
a unique morphism γ_ : V × W → P such that p_ ◦ γ_ = p and q_ ◦ γ_ = q (universal property of
P). The composite γ ◦ γ_ is the unique morphism V × W → V × W such that p ◦ γ ◦ γ_ = p and
q ◦ γ ◦ γ_ = q. But we already know one such morphism, namely, the identity morphism, and so
γ ◦ γ_ = id. Similarly γ_ ◦ γ = id, and so γ and γ_ are inverse isomorphisms.
Algebraic Geometry: 3. Algebraic Varieties 49
Before we can define products of algebraic varieties, we need to review tensor
products.
Review of tensor products. Let A and B be k-algebras. A k-algebra C together
with homomorphisms i : A → C and j : B → C is called the tensor product of A and
B if it has the following universal mapping property:fo r every pair of homomorphisms
(of k-algebras) α: A → R and β : B → R, there is a unique homomorphism γ : C → R
such that γ ◦ i = α and γ ◦ j = β:
A
i ✲ C ✛ j
B
❅
❅
α ❅❘ ✠_
_
_
β
R.
∃!
❄
.....
γ
Clearly, if the tensor product exists, it is uniquely determined up to a unique isomorphism
(same argument as in the above footnote). We write it A ⊗k B.
Construction. Let C∗ be the k-vector space with basis A × B. Thus the elements of
C∗ are finite sums
_
ci(ai, bi) with ci ∈ k, ai ∈ A, bi ∈ B. Let D be the subspace of
C∗ generated by the following elements,
(a + a_, b) − (a, b) − (a_, b), a, a_ ∈ A, b ∈ B,
(a, b + b
_
) − (a, b) − (a, b
_
), a∈ A, b, b
_ ∈ B,
(ca, b) − c(a, b), a∈ A, b ∈ B, c ∈ k,
(a, cb) − c(a, b), a∈ A, b ∈ B, c ∈ k,
and define C = C∗/D. Write a⊗b for the class of (a, b) in C — we have imposed the
fewest conditions forcing (a, b) _→ a ⊗ b to be k-bilinear. Every element of C can be
written as a finite sum,
_
ai ⊗ bi, ai ∈ A, bi ∈ B, and the map
A × B → C, (a, b) _→ a ⊗ b
is k-bilinear. By definition, C is a k-vector space, and there is a product structure on
C such that (a ⊗ b)(a_ ⊗ b_) = aa_ ⊗ bb_ — for this one has to check that the map
C
∗ × C
∗ → C, ((a, b), (a
_
, b
_
)) _→ aa
_ ⊗ bb
_
factors through C × C. It becomes a k-algebra by means of the homomorphism
c _→ c(1 ⊗ 1) = c ⊗ 1 = 1 ⊗ c. The maps
a _→ a ⊗ 1: A → C and b _→ 1 ⊗ b : B → C
are homomorphisms, and it is routine to check that they make C into the tensor
product of A and B in the above sense.
Example 3.13. The algebra B, together with the given map k → B and the
identity map B → B, has the universal property characterizing k ⊗k B. In terms of
the constructive definition of tensor products, the map c⊗b _→ cb : k⊗k B → B is an
isomorphism.
50 Algebraic Geometry: 3. Algebraic Varieties
Example 3.14. (a) The ring k[X1, . . . ,Xm,Xm+1, . . . ,Xm+n], together with the
maps
k[X1, . . . ,Xm] −o−bv−i−ou−s−in−cl−us−io→n k[X1, . . . ,Xm+n] ←ob−v−io−u−s i−nc−lu−s−io−n k[Xm+1, . . . ,Xm+n]
is the tensor product of k[X1, . . . ,Xm] and k[Xm+1, . . . ,Xm+n]. To verify this we
only have to check that, for every k-algebra R, the map
Homk-alg(k[X1, . . . ,Xm+n], R) → Homk-alg(k[X1, . . . ], R) × Homk-alg(k[Xm+1, . . . ], R)
induced by the inclusions is a bijection. But this map can be identified with the
bijection
Rm+n → Rm × Rn.
In terms of the constructive definition of tensor products, the map
f ⊗ g _→ fg: k[X1, . . . ,Xm] ⊗k k[Xm+1, . . . ,Xm+n] → k[X1, . . . ,Xm+n]
is an isomorphism.
(b) Let a and b be ideals in k[X1, . . . ,Xm] and k[Xm+1, . . . ,Xm+n] respectively,
and let (a, b) be the ideal in k[X1, . . . ,Xm+n] generated by the elements of a and b.
Then there is an isomorphism
f ⊗ g _→ fg:
k[X1, . . . ,Xm]
a
⊗k
k[Xm+1, . . . ,Xm+n]
b
→ k[X1, . . . ,Xm+n]
(a, b)
.
Again this comes down to checking that the natural map from
Homk-alg(k[X1, . . . ,Xm+n]/(a, b), R) to
Homk-alg(k[X1, . . . ,Xm]/a, R) × Homk-alg(k[Xm+1, . . . ,Xm+n]/b, R)
is a bijection. But the three sets are respectively
V (a, b) = zero-set of (a, b) in Rm+n,
V (a) = zero-set of a in Rm,
V (b) = zero-set of b in Rn,
and so this is obvious.
Remark 3.15. (a) If (bα) is a family of generators (resp. basis) for B as a k-vector
space, then (1⊗bα) is a family of generators (resp. basis) for A⊗kB as an A-module.
(b) Let k 8→ Ω be fields. Then
Ω ⊗k k[X1, . . . ,Xn]
∼=
Ω[1 ⊗ X1, . . . , 1 ⊗ Xn]
∼=
Ω[X1, . . . ,Xn].
If A = k[X1, . . . ,Xn]/(g1, . . . , gm), then
Ω ⊗k A
∼=
Ω[X1, . . . ,Xn]/(g1, . . . , gm).
For more details on tensor products, see Atiyah and MacDonald 1969, Chapter 2
(but note that the description there (p31) of the homomorphism A → D making the
tensor product into an A-algebra is incorrect — the map is a _→ f(a) ⊗1 = 1⊗ g(a).
Algebraic Geometry: 3. Algebraic Varieties 51
Products of affine varieties. The tensor product of two k-algebras A and B has the
universal property to be a product, but with the arrows reversed. Because of the
category anti-equivalence (2.14), this will show that Specm(A ⊗k B) is the product
of SpecmA and SpecmB in the category of affine algebraic varieties once we have
shown that A ⊗k B is an affine k-algebra.
Proposition 3.16. Let A and B be finitely generated k-algebras; if A and B are
reduced, then so also is A ⊗k B; if A and B are integral domains, then so also is
A ⊗k B.
Proof. Assume A and B to be reduced, and let α ∈ A⊗kB. Then α =
_n
i=1 ai⊗bi,
some ai ∈ A, bi ∈ B. If one of the bi’s is a linear combination of the remaining b’s,
say, bn =
_n−1
i=1 cibi, ci ∈ k, then, using the bilinearity of ⊗, we find that
α =
_n−1
i=1
ai ⊗ bi +
_n−1
i=1
cian ⊗ bi =
_n−1
i=1
(ai + cian) ⊗ bi.
Thus we can suppose that in the original expression of α, the bi’s are linearly independent
over k.
Now suppose that α is nilpotent, and let m be a maximal ideal in A. From a _→
 ̄a: A → A/m = k we obtain homomorphisms
a ⊗ b _→  ̄a ⊗ b _→  ̄ab : A ⊗k B → k ⊗k B
≈→
B
The image
_
 ̄aibi of α under this homomorphism is a nilpotent element of B, and
hence is zero (because B is reduced). As the bi’s are linearly independent over k, this
means that the  ̄ai are all zero. Thus, for all i, ai lies in every maximal ideal m of A,
and so is zero (by 2.12). Hence α = 0. This shows that A ⊗k B is reduced.
Assume A and B to be integral domains, and let α, α_ ∈ A⊗B be such that αα_ = 0.
As before, we can write α =
_
ai ⊗ bi and α_ =
_
a_
i
⊗ b_
i with the sets {b1, b2, . . . }
and {b_
1, b_
2, . . . } each linearly independent over k. For each maximal ideal m of A, we
know (
_
 ̄aibi)(
_
 ̄a_
ib_
i) = 0 in B, and so either (
_
 ̄aibi) = 0 or (
_
 ̄a_
ib_
i) = 0. Thus
either all the ai ∈ m or all the a_
i
∈ m. This shows that
specm(A) = V (a1, . . . , am) ∪ V (a
_
1, . . . , a
_
n).
Since specm(A) is irreducible (see 1.15), we must have specm(A) = V (a1, . . . , am) or
V (a_
1, . . . , a_
n). In the first case α = 0, and in the second α_ = 0.
Example 3.17. We give some examples to illustrate that k must be taken to be
algebraically closed in the proposition.
(a) Suppose k is nonperfect of characteristic p. To say that k is not perfect means
that there is an element α in an algebraic closure of k such that α /∈ k but αp ∈ k.
Let k_ = k[α], αp = a ∈ k, α /∈ k. Then (α ⊗ 1 − 1 ⊗ α) _= 0 in k_ ⊗k k_ (in fact, the
elements αi ⊗ αj, 0 ≤ i, j ≤ p − 1, form a basis for k_ ⊗k k_ as a k-vector space), but
(α ⊗ 1 − 1 ⊗ α)p = (a ⊗ 1 − 1 ⊗ a) = (1 ⊗ a − 1 ⊗ a) = 0.
Thus k_ ⊗k k_ is not reduced, even though k_ is a field.
(b) Let K be a finite separable extension of k and let Ω be a “big” field containing k
(for example an algebraic closure of k). Write K = k[α] = k[X]/(f(X)), and assume
52 Algebraic Geometry: 3. Algebraic Varieties
f(X) splits in Ω[X], say, f(X) =
_
X − αi. Because K/k is separable, the αi are
distinct, and so
K ⊗k Ω
∼=
Ω[X]/(f(X))
∼=
Ω[X]/(X − αi),
and so it is not an integral domain. (The second isomorphism follows from the Chinese
remainder theorem.)
Having (3.16), we can make the following definition:l et V and W be affine varieties,
and let Γ(V,OV) = A and Γ(W,OW) = B; then V × W = Specm(A ⊗k B) with
the projection maps p: V × W → V and q : V × W → W defined by the maps
a _→ a ⊗ 1: A → A ⊗k B and b _→ 1 ⊗ b : B → A ⊗k B.
Proposition 3.18. Let V and W be affine varieties; the projection maps p: V ×
W → V , q : V × W → W are regular, and a map ϕ: U → V × W is regular if and
only if p ◦ ϕ and q ◦ ϕ are regular. Therefore (V ×W, p, q) is the product of V and W
in the category of algebraic prevarieties. If V and W are irreducible, then so also is
V ×W.
Proof. The projection maps are regular because they correspond to the k-algebra
homomorphisms k[V ] → k[V ]⊗k k[W] and k[W] → k[V ]⊗k k[W]. Let ϕ: U → V ×W
be a map (of sets) such that p◦ϕ and q◦ϕ are regular. If U is affine, then ϕ corresponds
to the map k[V ] ⊗ k[W] → k[U] induced by
f _→ f ◦ (p ◦ ϕ) : k[V ] → k[U] and f _→ f ◦ (q ◦ ϕ) : k[W] → k[U],
and so is regular. This shows that, for a general U, the restriction of ϕ to every open
affine of U is regular, and this implies that ϕ is regular (see 3.5).
The final statement follows from the second statement in 3.16.
Example 3.19. (a) It follows from (3.14a) that
Am p←
Am+n q→ An,
where
p(a1, . . . , am+n) = (a1, . . . , am),
q(a1, . . . , am+n) = (am+1, . . . , am+n),
is the product of Am and An.
(b) It follows from (3.14b) that
V (a)
p←
V (a, b)
q→
V (b)
is the product of V (a) and V (b).
Warning! The topology on V ×W is not the product topology; for example, the
topology on A2 = A1 × A1 is not the product topology.
Products in general. Now let V and W be two algebraic prevarieties V and W.
We define their product as follows:A s a set, we take V × W. Now write V and W
as unions of open affines, V = ∪Vi, W = ∪Wj. Then V × W = ∪Vi × Wj, and we
give V ×W the topology for which U ⊂ V ×W is open if and only if U ∩ (Vi ×Wj)
is open for all i and j. Finally, we define a ringed space structure by saying that a
Algebraic Geometry: 3. Algebraic Varieties 53
function f : U → k on an open subset U is regular if its restriction to U ∩ (Ui × Vj)
is regular for all i and j.
Proposition 3.20. With the above structure, V ×W is a prevariety, the projection
maps
p: V ×W → V , q : V ×W → W
are regular, and a map ϕ: U → V × W is regular if and only if p ◦ ϕ and q ◦ ϕ
are regular. Therefore (V × W, p, q) is the product of V and W in the category of
prevarieties.
Proof. Straightforward.
Proposition 3.21. If V and W are separated, then so also is V ×W.
Proof. Straightforward.
Example 3.22. An algebraic group is a variety G together with regular maps
mult : G × G → G, inverse: G → G,
and an element e ∈ G that make G into a group in the usual sense. For example, SLn
and GLn are algebraic groups, and any finite group can be regarded as an algebraic
group. Connected affine algebraic groups are called linear algebraic groups because
they can all be realized as closed subgroups of GLn for some n, and connected algebraic
groups that can be realized as closed algebraic subvarieties of a projective space are
called abelian because they are related to the integrals studied by Abel.
Coarse Classification:e very algebraic group contains a sequence of normal subgroups
G ⊃ G0 ⊃ G1 ⊃ {e} with G/G0 a finite group, G0/G1 an abelian variety, and
G1 a linear algebraic group.
The separation axiom. Now that we have the notion of the product of varieties,
we can restate the separation axiom in terms of the diagonal.
By way of motivation, consider a topological space V and the diagonal Δ ⊂ V ×V ,
Δ df = {(x, x) | x ∈ V }.
If Δ is closed (for the product topology), then every pair of points (x, y) /∈
Δ has a
neighbourhood U × U_ such that U × U_ ∩Δ = ∅. In other words, if x and y are
distinct points in V then there are neighbourhoods U and U_ of x and y respectively
such that U ∩U_ = ∅. Thus V is Hausdorff. Conversely, if V is Hausdorff, the reverse
argument shows that Δ is closed.
For a variety V , we let Δ = ΔV (the diagonal) be the subset {(v, v) | v ∈ V } of
V × V .
Proposition 3.23. An algebraic prevariety V is separated if and only if ΔV is
closed.
Proof. Assume Δ to be closed, and let ϕ and ψ be regular maps Z → V. The
map
(ϕ, ψ) : Z → V × V , z _→ (ϕ(z), ψ(z))
54 Algebraic Geometry: 3. Algebraic Varieties
is regular, because its composites with the projections to V are ϕ and ψ. In particular,
it is continuous, and so (ϕ, ψ)−1(Δ) is closed. But this is precisely the subset on which
ϕ and ψ agree.
Conversely, suppose V is separated. By definition, this means that for any prevariety
Z and regular maps ϕ, ψ: Z → V , the set on which ϕ and ψ agree is closed in
Z. Apply this with ϕ and ψ the two projection maps V ×V → V , and note that the
set on which they agree is Δ.
Corollary 3.24. For any prevariety V , the diagonal is a locally closed subset of
V × V .
Proof. Let P ∈ V , and let U be an open affine neighbourhood of P. Then U ×U
is a neighbourhood of (P, P) in V × V , and ΔV ∩ (U × U) = ΔU, which is closed in
U × U because U is separated.
Thus ΔV is always a subvariety of V × V , and it is closed if and only if V is
separated.
The graph Γϕ of a regular map ϕ: V → W is defined to be
{(v,ϕ(v)) ∈ V ×W | v ∈ V }.
At this point, the reader should draw a picture, suggested by calculus.
Corollary 3.25. For any morphism ϕ: V → W of prevarieties, the graph Γϕ of
ϕ is locally closed in V ×W, and it is closed if W is separated. The map v _→ (v,ϕ(v))
is an isomorphism of V onto Γϕ.
Proof. The first statement follows from the preceding corollary because the graph
is the inverse image of the diagonal of W ×W under the regular map
(v,w) _→ (ϕ(v), w) : V ×W → W × W.
The second follows from the fact that the regular map Γϕ 8→ V × W
p→
V is an
inverse to v _→ (v,ϕ(v)) : V → Γϕ.
Theorem 3.26. The following three conditions on a prevariety are equivalent:
(a) V is separated;
(b) for every pair of open affines U and U_ in V , U ∩ U_ is an open affine, and
Γ(U ∩ U_,OV ) is generated by the functions P _→ f(P)g(P), f ∈ Γ(U,OV ),
g ∈ Γ(U_,OV ), i.e., the map k[U] ⊗k k[U_] → k[U ∩ U_] is surjective;
(c) the condition in (b) holds for the sets in some open affine covering of V .
Proof. Let Ui and Uj be open affines in V . We shall prove:
(i) Δ closed ⇒ Ui ∩ Uj affine.
(ii) If Ui ∩ Uj is affine, then
(Ui × Uj) ∩Δ is closed ⇐⇒ the map k[Ui] ⊗k k[Uj ] → k[Ui ∩ Uj ] is surjective.
If {Ui × Uj}(i,j)∈I×J is an open covering of V × V , Δ is closed in V × V ⇐⇒
Δ ∩ (Ui × Uj) is closed in Ui × Uj for each pair (i, j). Thus these statements show
that (a)⇒(b) and (c)⇒(a). Since the implication (b)⇒(c) is trivial, this shows that
(i) and (ii) imply the theorem.
Algebraic Geometry: 3. Algebraic Varieties 55
Proof of (i):T he graph of the inclusion ι : Ui ∩ Uj 8→ V is Γι = (Ui × Uj) ∩ Δ ⊂
(Ui ∩ Uj)×V . If Δ is closed, (Ui ×Uj) ∩Δ is a closed subvariety of an affine variety,
and hence is affine (see p45). Since Ui ∩ Uj ≈ Γι, it also is affine.
Proof of (ii):No w assume that Ui ∩ Uj is affine. Then (Ui × Uj) ∩ ΔV is closed in
Ui×Uj ⇐⇒ v _→ (v, v) : Ui∩Uj → Ui×Uj is a closed immersion ⇐⇒ the morphism
k[Ui ×Uj ] → k[Ui ∩ Uj ] is surjective (see 2.21). Since k[Ui ×Uj] = k[Ui]⊗k k[Uj ], this
completes the proof of (ii).
Example 3.27. (a) Let V = P1, and let U0 and U1 be the standard open subsets
(Ui = A1). Then U0 ∩ U1 = A1 − {0}, and the maps on rings corresponding to the
inclusions Ui 8→ U0 ∩ U1 are k[X] → k[X,X−1], X _→ X, and k[X] → k[X,X−1],
X _→ X−1. Thus the sets U0 and U1 satisfy the condition in (b).
(b) Let V be A1 with the origin doubled (see 3.10), and let U and U_ be the upper
and lower copies of A1 in V. Then U ∩ U_ is affine, but k[U] ⊗ k[U_] → k[U ∩ U_] is
not surjective. In fact the map is
k[X] ⊗ k[Y ] = k[X, Y ] → k[X,X−1], X_→ X, Y _→ X.
(c) Let V be A2 with the origin doubled, and let U and U_ be the upper and lower
copies of A2 in V . Then U ∩ U_ is not affine (see 2.20).
Dimension. Let V be an irreducible algebraic variety. Then every open subset of V
is dense, and is irreducible. If U ⊃ U_ are open affines in V , then we have
k[U] ⊂ k[U
_
] ⊂ k(U).
Therefore k(U) is also the field of fractions of k[U_]. This remark shows that we can
attach to V a field k(V ), called the field of rational functions on V , such that for
every open affine U in V , k(V ) is the field of fractions of k[U]. The dimension of V
is defined to be the transcendence degree of k(V ) over k. Note the dim(V) = dim(U)
for any open subset U of V . In particular, dim(V) = dim(U) for U an open affine in
V . It follows that some of the results in §1 carry over — for example, if Z is a proper
closed subvariety of V , then dim(Z) < dim(V ).
Proposition 3.28. Let V and W be irreducible varieties. Then
dim(V ×W) = dim(V ) + dim(W).
Proof. We can assume V and W to be affine, and write k[V ] = k[x1, . . . , xm] and
k[W] = k[y1, . . . , yn] where {x1, . . . , xd} and {y1, . . . , ye} are maximal algebraically
independent sets of elements of k[V ] and k[W]. Thus d = dim(V ) and e = dim(W).
Then12
k[V ×W] = k[V ] ⊗k k[W] ⊃ k[x1, . . . , xd] ⊗k k[y1, . . . , ye] ≈ k[x1, . . . , xd, y1, . . . , ye].
Therefore {x1 ⊗1, . . . , xd ⊗1, 1⊗y1, . . . , 1⊗ye} will be algebraically independent in
k[V ]⊗k k[W]. Obviously k[V ×W] is generated as a k-algebra by the elements xi⊗1,
1 ⊗ yj, 1 ≤ i ≤ m, 1 ≤ j ≤ n, and all of them are algebraic over
k[x1, . . . , xd] ⊗k k[y1, . . . , ye].
12In general, it is not true that if M_ and N_ are R-submodules of M and N, then M_ ⊗R N_ is
an R-submodule of M ⊗R N. However, this is true if R is a field, because then M_ and N_ will be
direct summands of M and N, and tensor products preserve direct summands.
56 Algebraic Geometry: 3. Algebraic Varieties
Thus the transcendence degree of k(V ×W) is d + e.
We extend the definition to an arbitrary variety V as follows. A variety is a
finite union of Noetherian topological spaces, and so is Noetherian. Consequently
(see 1.17), V is a finite union V = ∪Vi of its irreducible components, and we define
dim(V ) = maxdim(Vi).
An algebraic variety as a functor of affine k-algebras. Let A be an affine kalgebra,
and let V be an algebraic variety. We define a point of V with coordinates
in A to be a regular map Specm(A) → V . For example, if V = V (a) ⊂ kn, then
V (A) = {(a1, . . . , an) ∈ An | f(a1, . . . , an) = 0 all f ∈ a},
which is what you expect. In particular V (k) = V (as a set), i.e., V (as a set) can be
identified with the set of points of V with coordinates in k. Note that (V ×W)(A) =
V (A) ×W(A).
Theorem 3.29. A regular map ϕ: V → W of algebraic varieties defines a family
of maps of sets, ϕ(A) : V (A) → W(A), one for each affine k-algebra A, such that for
every homomorphism α: A → B of k-algebras,
A V(A)
ϕ(A)
>W(A)
(*)
B
∨
α
V (B)
∨
V (α)
ϕ(B)
> V (B)
∨
W(α)
commutes. Every family of maps with this property arises from a unique morphism
of algebraic varieties.
The proof is trivial, once one has made the correct definitions, which we do in the
next subsection.
Categories and functors. A category C consists of
(a) a class of objects ob(C);
(b) for each pair (A,B) of objects, a set Mor(A,B), whose elements are called
morphisms from A to B, and are written α: A → B;
(c) for each triple of objects (A,B,C) a map (called composition)
(α, β) _→ β ◦ α:Mo r(A,B) × Mor(B,C) → Mor(A,C).
Composition is required to be associative, i.e., (γ ◦ β) ◦α = γ ◦ (β ◦α), and for each
object A there is required to be an element idA ∈ Mor(A,A) such that idA ◦α = α,
β ◦ idA = β, for all (appropriate) α and β. The sets Mor(A,B) are required to be
disjoint (so that a morphism α determines its source and target).
Example 3.30. (a) There is a category of sets, Sets, whose objects are the sets
and whose morphisms are the usual maps of sets.
(b) There is a category Affk of affine k-algebras, whose objects are the affine kalgebras
and whose morphisms are the homomorphisms of k-algebras.
(c) There is a category Vark of algebraic varieties over k, whose objects are the
algbraic varieties over k and whose morphisms are the regular maps.
Algebraic Geometry: 3. Algebraic Varieties 57
The objects in a category need not be sets with structure, and the morphisms need
not be maps.
Exercise 3.31. List twenty more examples of categories.
Let C and D be categories. A covariant functor F from C to D consists of
(a) a map A _→ F(A), sending each object of C to an object of D, and,
(b) for each pair of objects A,B of C, a map
α _→ F(α):M or(A,B) → Mor(F(A), F(B))
such that F(idA) = idF(A) and F(β ◦ α) = F(β) ◦ F(α).
A contravariant functor is defined similarly, except that the map on morphisms is
α _→ F(α):M or(A,B) → Mor(F(B), F(A))
A functor F : C → D is fully faithful if, for all objects A and B of C, the map
Mor(A,B) → Mor(F(A), F(B))
is a bijection. Then F defines an equivalence of C with the full subcategory of D
whose objects are isomorphic to F(A) for some object A of C (see p42). For example,
the functor A _→ SpecmA is fully faithful contravariant functor Affk → Vark, and
defines an equivalence of the first category with the subcategory of the second whose
objects are the affine algebraic varieties.
Example 3.32. (a) For any object V of a category C, we have a contravariant
functor
hV : C → ____________Sets,
which sends an object A to the set Mor(A, V ) and sends a morphism α: A → B to
ϕ _→ ϕ ◦ α: hV (B) → hV (A),
i.e., hV (∗) =Mor(∗, V ) and hV (α) = ∗ ◦ α.
(b) We have a contravariant functor
V _→ Γ(V,OV ) : Vark → Affk.
Let F and G be two functors C → D. A morphism α: F → G is a collection of
morphisms α(A) : F(A) → G(A), one for each object A of C, such that, for every
morphism u: A → B in C, the following diagram commutes:
A F(A)
α(A)
>G(A)
(**)
B
∨
u
F(B)
∨
F(u)
α(B)
>G(B)
∨
G(u)
.
Example 3.33. Let α: V → W be a morphism in C. The collection of maps
hα(A) : hV (A) → hW(A), ϕ_→ α ◦ ϕ
is a morphism of functors.
With this notion of morphism, the functors C → D form a category Fun(C,D)
(we ignore the problem that Mor(F,G) may not be a set — only a class).
58 Algebraic Geometry: 3. Algebraic Varieties
Proposition 3.34 (Yoneda Lemma). The functor
V _→ hV : C → Fun(C, Sets)
is fully faithful.
Proof. Let A,B be objects of C. We construct an inverse to
α _→ hα:Mo r(A,B) → Mor(hA, hB).
For a morphism of functors γ : hA → hB, define β(γ) = γ(idA)—it is morphism
A → B. Then
β(hα) df = hα(idA) df = α ◦ idA = α,
and
hβ(γ)(α) df = β(γ) ◦ α df = γ(idA) ◦ α = γ(α)
because of the commutativity of (**):
A hA(A)
γ
> hB(A)
(***)
B
∨
α
hB(B)
∗◦α
∨
γ
> hB(B)
∨
∗◦α
Thus α → hα and γ _→ β(γ) are inverse maps.
Algebraic varieties as functors (continued). The Yoneda lemma shows that the
functor V _→ hV embeds the category of affine algebraic varieties as a full subcategory
of the category of covariant functors Affk → Sets, and it is not difficult to deduce
that it embeds the category of all algebraic varieties in to the category of such functors
(use 3.12 for example). This proves (3.29).
It is not unusual for a variety to be most naturally defined in terms of its points
functor. For example, for any affine k-algebra, let SLn(A) be the group of n × n
matrices with coefficients in A having determinant 1. A homomorphism A → B
induces a homomorphism SLn(A) → SLn(B), and so SLn(A) is a functor. In fact, it
is the points functor of the affine variety:
Specm k[X11, . . . ,Xnn]/(det(Xij) − 1).
Matrix multiplication defines a morphism of functors
SLn ×SLn → SLn
which, because of (3.29), arises from a morphism of algebraic varieties. In fact, SLn
is an algebraic group.
Instead of defining varieties to be ringed spaces, it is possible to define them to be
functors Affk → Sets satisfying certain conditions.
Dominating maps. A regular map α: V → W is said to be dominating if the
image of α is dense in W. Suppose V and W are irreducible. If V _ and W_ are open
affine subsets of V and W such that ϕ(V _) ⊂ W_, then (2.21) implies that the map
f _→ f ◦ ϕ: k[W_] → k[V _] is injective. Therefore it extends to a map on the fields of
fractions, k(W) → k(V ), and this map is independent of the choice of V _ and W_.
Algebraic Geometry: 4. Local Study 59
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