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1.5 Some Classical Jargon
We write 1 + i0 as 1, a+i0 as a, 0+ib as ib. In particular, the origin 0 + i0
is written 0.
You will often _nd 4 + 3i written when strictly speaking it should be 4 + i3.
This is one of the di_erences that don't make a di_erence.
We use the following notation: <(x + iy) = x which is read: 'The real part
of the complex number x+iy is x.'
And
=(x + iy) = y which is read : 'The imaginary part of the complex number
x+iy is y.' The = sign is a letter I in a font derived from German Blackletter.
Some books use 'Re(x+iy)' in place of <(x + iy) and 'Im(x+iy)' in place of
=(x + iy).
We also write
x + iy = xiy, and call _z the complex conjugate of z for any complex number
z.
1.5. SOME CLASSICAL JARGON 23
Notice that the complex conjugate of a complex number in matrix form is
just the transpose of the matrix; reect about the principal diagonal.
The following 'fact' will make some computations shorter:
jzj2 = z_z
Verify it by writing out z as x + iy and doing the multiplication.
Exercise 1.5.1 Draw the triangle obtained by taking a line from the origin
to the complex number x+iy, drawing a line from the origin along the X axis
of length x, and a vertical line from (x,0) up to x+iy. Mark on this triangle
the values jx + iyj, <(x + iy) and =(x + iy).
Exercise 1.5.2 Mark on the plane a point z = x + iy. Also mark on z
and _z.
Exercise 1.5.3 Verify that __z = z for any z.
The exercises will have shown you that it is easy to write out a complex
number in Polar form. We can write
z = x + iy = r(cos _ + i sin _)
where _ = arccos x = arcsin y, and r = jzj.
We write:
arg(z) = _ in this case. There is the usual problem about adding multiples
of 2_, we take the principal value of _ as you would expect. arg(0 + 0i) is
not de_ned.
Exercise 1.5.4 Calculate arg(1 + i)
I apologise for this jargon; it does help to make the calculations shorter after
a bit of practice, and given that there have been four centuries of history to
accumulate the stu_, it could be a lot worse.
24 CHAPTER 1. FUNDAMENTALS
In general, I am more concerned with getting the ideas across than the jargon,
which often obscures the ideas for beginners. Jargon is usually used to keep
people from understanding what you are doing, which is childish, but the
method only works on those who haven't seen it before. Once you _gure out
what it actually means, it is pretty simple stu_.
Exercise 1.5.5 Show that
1
z
=
_z
z_z
Do it the long way by expanding z as x + iy and the short way by cross
multiplying. Is cross multiplying a respectable thing to do? Explain your
position.
Note that z_z is always real (the i component is zero). Use this for calculating
1
4 + 3i
and
1
5 + 12i
Express your answers in the classical form a+ib.
Exercise 1.5.6 Find 1
z when z = r(cos _ + i sin _) and express the answers
in polar form.
Exercise 1.5.7 Find 1
z when
z = _ a b
b a _
Express your answer in classical, point, polar and matrix forms.
Exercise 1.5.8 Calculate
2 i3
5 + i12
Express your answer in classical, point, polar and matrix forms.
It should be clear from doing the exercises, that you can _nd a multiplicative
inverse for any complex number except 0. Hence you can divide z by w for
any complex numbers z and w except when w = 0.
This is most easily seen in the matrix form:
1.5. SOME CLASSICAL JARGON 25
Exercise 1.5.9 Calculate the inverse matrix to
z = _ a b
b a _
and show it exists except when both a and b are zero
The classical jargon leads to some short and neat arguments which can all
be worked out by longer calculations. Here is an example:
Proposition 1.5.1 (The Triangle Inequality) For any two complex numbers
z, w:
jz + wj _ jzj+jwj
Proof:
jz + wj
2 = (z + w)(z + w)
= (z + w)(_z + _ w)
= z_z + z _ w + w_z + w _ w
= jzj
2 + z _ w + w_z + jwj
2
= jzj
2 + z _ w + z _ w + jwj
2
= jzj
2 + 2<(z _w) + jwj
2
_ jzj
2 + 2j<(z _ w)j + jwj
2
_ jzj
2 + 2jz _wj+jwj
2
_ (jzj+j _wj)2
Hence
jz + wj _ jzj+jwj
since jwj = j _ wj. 2
Check through the argument carefully to justify each stage.
Exercise 1.5.10 Prove that for any two complex numbers z;w; jzwj = jzjjwj.
26 CHAPTER 1. FUNDAMENTALS
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